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saul85 [17]
3 years ago
10

-3 squared + 4.6 times (- 0.1)

Mathematics
1 answer:
malfutka [58]3 years ago
6 0
Your answer would be
- 9.46
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Calculate the constant of variation if y varies directly as x.
timama [110]
You have not provided the complete question (value of y at a certain value of x), therefore, I cannot give u a specific final answer. However, I can explain how to solve this problem and you can apply on the numbers you have.

y varies directly with x means that as x increases, y also increases and vice versa.
This can be represented by the following equation:
y = kx
where k is the constant of proportionality.

Solving this for k, we would find that:
k = y/x

Examples:
If we are given that y = 4 at x = 2, then:
k = y/x = 4/2 = 2
If we are given that y = 1 at x = 3, then:
k = y/x = 1/3
In general, if we are given that y = a at x = b, then:
k = a/b

Hope this helps :)
6 0
3 years ago
Trinity created a game that uses a card number 1 to 8 and a six sided cube numbered 1 to 6. Each player chooses one card and roa
Ksju [112]

Answer:

Correct option: A -> 1/24

Step-by-step explanation:

To find the probability of having a card with the value greater than six, the options are: 7 and 8. So there are two options in the total of 8, so the probability is P1 = 2 / 8 = 1/4

The cube has 6 numbers, from 1 to 6, so the probability of rolling a six is P2 = 1/6

To find the final probability, we multiply both probabilities, so:

P = P1 * P2 = (1/4) * (1/6) = 1/24

Correct option: A

8 0
3 years ago
The table reflects the prices at Strike-O-Rama Bowling Alley.
Goshia [24]

Answer: the answer is 4.95

Step-by-step explanation:

8 0
3 years ago
Transactions to a computer database are either new items or changes to previous items. the addition of an item can be completed
sashaice [31]

P(<100) = P((new or change) & <100) = P(new & <100) + P(change & <100)

... = P(<100 | new)*P(new) + P(<100 | change)*P(change)

... = 0.90*0.70 + 0.20*0.30

... = 0.63 + 0.06 = 0.69 . . . . probability of completing a transaction in < 100 ms

4 0
3 years ago
How to write 85,000,011 in expanded form
4vir4ik [10]

85,000,000 + 000,000 + 000 + 11

I'm not sure if this is right because I haven't done expanded form in years. If it isn't, I'm sorry.

6 0
3 years ago
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