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saveliy_v [14]
3 years ago
15

A gas measuring 525 mL is collected at 104.66 kPa. What volume does this gas

Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Recall the ideal gas law:

<em>P V</em> = <em>n R T</em>

where

<em>P</em> = pressure

<em>V</em> = volume

<em>n</em> = number of gas molecules

<em>R</em> = ideal gas constant

<em>T</em> = temperature

If both <em>n</em> and <em>T</em> are fixed, then <em>n R T</em> is a constant quantity, so for two pressure-volume pairs (<em>P</em>₁, <em>V</em>₁) and (<em>P</em>₂, <em>V</em>₂), you have

<em>P</em>₁ <em>V</em>₁ = <em>P</em>₂ <em>V</em>₂

(since both are equal to <em>n R T </em>)

Solve for <em>V</em>₂ :

<em>V</em>₂ = <em>P</em>₁ <em>V</em>₁ / <em>P</em>₂ = (104.66 kPa) (525 mL) / (25 kPa) = 2197.86 mL

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