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4 years ago

Simplify the following expression: 1/8 + 1/16 = ?

Mathematics

2 answers:

alekssr [168]4 years ago

5 0

Add them and you will get 3/16... 0.1875 in decimal form

devlian [24]4 years ago

3 0

Step by step may help
Step 1: change the denominator of 1/8 to 16
Step 2: add the too fractions together
Step 3: get an awnser of 0.187 or 18.75 as a percentage

Hope this helps u!

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A rectangle has a height of k^2+3k 2 +3k, squared, plus, 3 and a width of k^2+7k 2 +7k, squared, plus, 7. Express the area of th

vlada-n [284]

Answer: $k^4+10k^3+21k^2$

Step-by-step explanation:

Given

Height of rectangle is $h=k^2+3k$

Width is $w=k^2+7k$

The area of the rectangle is given by the multiplication of the height and width

$\Rightarrow A=\left(k^2+3k\right)\left(k^2+7k\right)\\\\\Rightarrow A=k^2k^2+k^2\cdot \:7k+3kk^2+3k\cdot \:7k\\\\\Rightarrow A=k^4+10k^3+21k^2$

Thus, the area of the rectangle is $k^4+10k^3+21k^2$ .

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3 years ago

The legs of an isosceles triangle measure ( 2 x^4 + 2 x − 1 ) units each. The perimeter of the triangle is ( 5 x^4 − 2 x^3 + x −

nirvana33 [79]

Answer:

The base is x^4 -2x^3 -3x-1

Step-by-step explanation:

We know the perimeter of a triangle is the sum of the three sides

P = s1+s2+s3

We know the perimeter is 5 x^4 − 2 x^3 + x − 3

and two of the legs are 2 x^4 + 2 x − 1 since it is an isosceles triangle

P = 2s1 + s3

Subtract 2s1 from each side

P-2s1 =2s1 +s3 -2S1

P -2s1 =s3

Substituting what we know

5 x^4 − 2 x^3 + x − 3 - 2(2 x^4 + 2 x − 1) = s3

Distribute the -2

5 x^4 − 2 x^3 + x − 3 - 4 x^4 -4 x + 2 = s3

Combine like terms

5 x^4-4x^4 − 2 x^3 + x -4 x -3+ 2 = s3

x^4 -2x^3 -3x-1 =s3

The base is x^4 -2x^3 -3x-1

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3 years ago

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3 years ago

The ball is shaped like a hemisphere with a radius of 5 inches. Find the volume of the bowl

PilotLPTM [1.2K]

Answer:

The volume of the bowl is $V=\frac{250}{3}\pi\ in^{3}$ or $V=83\frac{1}{3}\pi\ in^{3}$

Step-by-step explanation:

we know that

The volume of a hemisphere (bowl) is equal to

$V=\frac{4}{6}\pi r^{3}$

we have

$r=5\ in$

substitute

$V=\frac{4}{6}\pi (5)^{3}$

$V=\frac{250}{3}\pi\ in^{3}$

$V=83\frac{1}{3}\pi\ in^{3}$

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Step-by-step explanation:

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