The amount of money worker will take home is €24752.6
<h3>What is gross pay?</h3>
Gross pay is the amount earned by any individual without any deductions of the taxes, and charges. It is the total amount of money earned by anyone.
Given that:-
- The gross pay of a worker in a factory is €30800.60 per annum. If €504 is deducted from his salary month.
The amount of money he will take home will be calculated as:-
Gross pay = €30800.60
Deductions = €504 per month = 504 x 12 = €6048 per year.
So net pay = 30800.6 - 6048 = €24752.6
Therefore the amount of money the worker will take home is €24752.6
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Answer:
The length as an algebraic expression in y is 
ft
Step-by-step explanation:
The measure of the width of the computer desk = y feet
The measure of the length of the desk = width + 2 1/4 ft
⇒Measure of Length = ft
Hence, the length as an algebraic expression in y is ft
Answer:
x = 136/11
, y = 68/11
Step-by-step explanation:
Solve the following system:
{6 x - y = 68
2 y = x
Hint: | Choose an equation and a variable to solve for.
In the second equation, look to solve for x:
{6 x - y = 68
2 y = x
Hint: | Reverse the equality in 2 y = x in order to isolate x to the left hand side.
2 y = x is equivalent to x = 2 y:
{6 x - y = 68
x = 2 y
Hint: | Perform a substitution.
Substitute x = 2 y into the first equation:
{11 y = 68
x = 2 y
Hint: | Choose an equation and a variable to solve for.
In the first equation, look to solve for y:
{11 y = 68
x = 2 y
Hint: | Solve for y.
Divide both sides by 11:
{y = 68/11
x = 2 y
Hint: | Perform a back substitution.
Substitute y = 68/11 into the second equation:
{y = 68/11
x = 136/11
Hint: | Sort results.
Collect results in alphabetical order:
Answer: {x = 136/11
, y = 68/11
First, we need to find the LCD (Least Common Denominator) so we can subtract them much easier.
An easy way to find the LCD is to just multiply the denominators together: So 2 • 5 = 10
We have to do the same to the numerators too though.
1/2 (5) = 5/10
2/5 (2) = 4/10
Now, the remade expression is:
5/10 - 4/10 which will equal 1/10.
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