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MatroZZZ [7]
3 years ago
9

Given that g(x)=x^2 find each of the following

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0

What are the following?


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Find the length of AC if AB = 16 and BC = 12.
enot [183]

AC = 28

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Katherine has 32 pop songs in 72 rock songs on her MP3 player that she will be organizing into paulista. Que want to por an eria
LUCKY_DIMON [66]

Answer: The greatest  number of playlist Katherine can make =8

Each of playlist will have 4 pop songs and 9 rock songs.


Step-by-step explanation:

Given: The number of pop songs Katherine has= 32

The number of rock songs Katherine has= 72

If she want to make playlist such that in each playlist there is equal number of pop and rock songs, we need to find the GCF(greatest common factor) of 32 and 72.

We know that 32=2\times2\times2\times2\times2\\72=2\times2\times2\times3\times3

We can see the GCF(32,72)=2\times2\times2=8

Hence, the greatest  number of playlist Katherine can make =8

The number of pop songs= \frac{32}{8}=4

the number of rock songs=\frac{72}{8}=9

Each of playlist will have 4 pop songs and 9 rock songs.


5 0
3 years ago
Which expression is equivalent to the some 30 + 12
Alecsey [184]

Answer:

give a picture

Step-by-step explanation:

5 0
3 years ago
Write the equation of the line that passes through the points
Strike441 [17]

Answer:

y= -1/2x +5.5

Step-by-step explanation:

hope this helps :)

4 0
3 years ago
I have some questions regarding combinations in finite. Here is my first one I am stumped on:
podryga [215]

We will get the number of possible selections, and then subtract the number less than 25 cents.

We can choose the number of dimes 5 ways 0,1,2,3 or 4.
We can choose the number of nickels 4 ways 0,1,2 or 3.
We can choose the number of quarters 3 ways 0,1, or 2.

That's 5*4*3  = 60 selections 

Now we must subtract from the 60 the number of selections of coins that are less than 25 cents. These will involve only dimes and nickels. 

To get a selection of coin worth less than 25 cents:
If we use no dimes, we can use 0,1,2  on all 3 nickels.
That's 4 selections less than 25 cents. (that includes the choice of No coins at all in the 60, which we must subtract).

If we use exactly 1 dime , we can use 0,1,2, or all 3 nickels.
That's the 3 combinations less than 25 cents.

And there is 1 other selection less than 25 cents, 2 dimes and no nickels. 

So that's 4+3+1 = 8 selections which we must subtract from the 60.
 
Answer 60-8 = 52 selections of coins worth 25 cents or more.

8 0
3 years ago
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