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3 years ago

Help me with this ASAP. Please and thank you

Mathematics

1 answer:

Whitepunk [10]3 years ago

4 0

Answer:

<1 + <2 = 180

Step-by-step explanation:

Looking at the diagram

<1+<2 forms a straight line so they add to 180 degrees

<1 + <2 = 180

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X squared plus 5 x equals zero

Scrat [10]

Answer:

Step-by-step explanation:

$x^{2} + 5x = 0$

On the left-hand side of the equation, both terms have a common factor of $x$ , so we can pull that out:

$x(x + 5) = 0$

We can now create two equations from this to solve for $x$ :

$x = 0$

$x + 5 = 0$

The first equation doesn't need any further work, but the second equation can be reduced by substracting $5$ from both sides to get $x$ by itself on the left-hand side:

$x = -5$

Therefore, the two solutions to the problem are $x = 0, -5$

7 0

4 years ago

What is the value of x in the equation -6 +x= -4?

Dafna11 [192]

Answer: x = 2

Step-by-step explanation:

-6 + x = -4

Add 6 to each side

x = 2

Now, if you plug that into the equation, you can check it.

-6 + 2 = -4

6 0

3 years ago

Read 2 more answers

The city is planning to add a fish pond to a neighborhood park. The figure below is a drawing of the fish pond. Its scale is 1/2

faust18 [17]

Answer:

Part a) The area of the actual fish pond is $2,956.50\ ft^{2}$

Part b) The length of the fence will be $244.20\ ft$

Step-by-step explanation:

we know that

The scale drawing is

$\frac{(1/2)}{15}\frac{in}{ft}=\frac{1}{30}\frac{in}{ft}$

step 1

Find the actual dimensions of the fish pond

To find the actual dimensions divide the measure of the drawing by the scale drawing

$0.5\ in=0.5/(1/30)=15\ ft$

$1\ in=1/(1/30)=30\ ft$

$2.5\ in=2.5/(1/30)=75\ ft$

step 2

Find the area of the actual fish pond

The area of the fish pond is equal to the area of a circle p[lus the area of rectangle

$A=\pi r^{2} +bh$

we have

$r=15\ ft$

$b=75\ ft$

$h=30\ ft$

substitute

$A=(3.14)(15)^{2} +(75)(30)=2,956.50\ ft^{2}$

step 3

Find the length of the fence around the entire fish pond

The perimeter of the fish pond is equal to the circumference of a complete circle plus the length of 75 ft two times

$P=2\pir+2(75)$

we have

$r=15\ ft$

substitute

$P=2(3.14)(15)+2(75)=244.20\ ft$

3 0

3 years ago

Richard, Henry and Gavin share some sweets in the ratio 5:4:3. Richard gets 70 sweets. How many sweets are there altogether?

maxonik [38]

There are 168 sweets altogether

<h3><u>Solution:</u></h3>

Richard, Henry and Gavin share some sweets in the ratio 5 : 4 : 3

Let "5a" be the share of Richard

Let "4a" be the share of Henry

Let "3a" be the share of Gavin

Richard gets 70 sweets

share of Richard = 70

5a = 70

To find: number of sweets altogether

number of sweets altogether = share of richard + share of henry + share of gavin

number of sweets altogether = 5a + 4a + 3a

number of sweets altogether = 12a = 12(14) = 168

Thus there are 168 sweets altogether

4 0

3 years ago

Previous 20 Two groups leave on different flights from the same airport. Group A flies 200 miles due south, then turns 68° towar

Oksana_A [137]

Answer:

Group B is farther from the airport.

Step-by-step explanation:

To find the distance of each group to the airport we can use the law of cosines in the triangle created with the two movements done and the resulting total distance.

Law of cosines:

$c^2 = a^2 + b^2 - 2ab*cos(angle)$

For group A, we have the sides of 200 miles and 75 miles, and the angle between the sides is (180-68) = 112°, so the third side of the triangle is:

$c^2 = 200^2 + 75^2 -2*200*75*cos(112)$

$c^2 = 56863.198$

$c = 238.46\ miles$

For group B, we also have the sides of 200 miles and 75 miles, and the angle between the sides is (180-51) = 129°, so the third side of the triangle is:

$c^2 = 200^2 + 75^2 -2*200*75*cos(129)$

$c^2 = 64504.612$

$c = 253.98\ miles$

The distance from group B to the airport is bigger, so group B is farther from the airport.

8 0

4 years ago