What is x?<br> 6x-8=8x-6

slavikrds [6]

Answer:

the slope is 4/3

Step-by-step explanation:

slope is also called rise over run you start at one point and count how many spaces it is up to the next point then across

8 0

3 years ago

Graph the line with the equation y= 1/2x -1

spayn [35]

Answer:

Start at the y-intercept, (0,-1). Next, go up one and to the right 2, plot a point. Keep going up one and to the right 2 until you reach the end of the graph. Next, go back to your y-intercept. Go down one and to the left 2. Keep going down and to the left until you reach the end of the graph. Connect all points.

Step-by-step explanation:

Start at the y-intercept, (0,-1). Next, go up one and to the right 2, plot a point. Keep going up one and to the right 2 until you reach the end of the graph. Next, go back to your y-intercept. Go down one and to the left 2. Keep going down and to the left until you reach the end of the graph. Connect all points.

4 0

3 years ago

Find the distance between the points with the given coordinates (-2, -5) and (-2, 4).

bija089 [108]

I hope this helps you

6 0

4 years ago

Factor completely:<br>64 - y^3

madam [21]

From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is $4^{3}$ , and $y^{3}$ .

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are $a^{3}$ and $b^{3}$ . The difference of those two cubes is:
$a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})$

In our problem, a = 4 (since $a^{3}$ = 64) and b = y (since $b^{3} = y^{3}$ . Plug these values into the rule to find the factor of $64 - y^3$ :
$64 - y^3 \\
= (4 - y)( 4^{2} + 4y + y^{2}) \\
= (4 - y)( 16 + 4y + y^{2})$

-----

Answer: $(4 - y)( 16 + 4y + y^{2})$

8 0

3 years ago

Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

3 years ago

What is x? 6x-8=8x-6