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Georgia [21]
4 years ago
12

Which expression is equivalent to (StartFraction (3 x y Superscript negative 5 Baseline) cubed Over (x Superscript negative 2 Ba

seline y squared) Superscript negative 4 Baseline) EndFraction) Superscript negative 2? Assume StartFraction x Superscript 10 Baseline y Superscript 14 Baseline Over 729 EndFraction.
StartFraction x Superscript 10 Baseline y Superscript 14 Baseline Over 729 EndFraction
StartFraction x Superscript 22 Baseline Over 18 y Superscript 46 Baseline EndFraction
StartFraction 729 Over x Superscript 10 Baseline y Superscript 14 Baseline EndFraction
StartFraction 18 y Superscript 46 Baseline Over x Superscript 22 Baseline EndFraction
Mathematics
2 answers:
marshall27 [118]4 years ago
8 0

Option a: \frac{x^{10} y^{14}}{729} is the correct answer.

Explanation:

The expression is \left(\frac{\left(3 x y^{-5}\right)^{3}}{\left(x^{-2} y^{2}\right)^{-4}}\right)^{-2}

We shall simplify the expression, to determine the expression which is equivalent to \left(\frac{\left(3 x y^{-5}\right)^{3}}{\left(x^{-2} y^{2}\right)^{-4}}\right)^{-2}

Multiplying the powers, we get,

\left(\frac{\left3^{3} x^{3} y^{-15}\right}{x^{8} y^{-8}}\right)^{-2}

Again multiplying the powers, we get,

\left\frac{\left3^{-6} x^{-6} y^{30}\right}{x^{-16} y^{16}}\right

Dividing the fractions, we have,

\left\frac{\left3^{-6} y^{14}\right}{x^{-10} }\right

Applying the exponent rule, a^{-b}=\frac{1}{a^{b}}, we have,

\frac{x^{10} y^{14}}{3^{6} }

Hence, the expression can be written as

\frac{x^{10} y^{14}}{729}

Thus, the expression which is equivalent to \left(\frac{\left(3 x y^{-5}\right)^{3}}{\left(x^{-2} y^{2}\right)^{-4}}\right)^{-2} is \frac{x^{10} y^{14}}{729}

Hence, Option a is the correct answer.

Norma-Jean [14]4 years ago
3 0

A.)‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎

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