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3 years ago

10

Help me please it’s hard

2 answers:

UNO [17]3 years ago

7 0

The answer is B!!

Hope this helps!!

Pie3 years ago

6 0

This is an alternating interior angle.

Alternating interior angle states that "The two angles that are alternating interior will be the same measurements."

with this, ∠x <span>≅ m</span>∠85°, ∴ m∠x = 85°

85° is your answer

hope this helps

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32. Parallelogram ABCD has vertices A(0,0), B(2,4), and C(10,4). Find the coordinates of D.

goblinko [34]

Answer:

The fourth vertex is D(8, 0)

Step-by-step explanation:

Let A(0, 0), B(2, 4), and C(10, 4) be the three vertices of a parallelogram ABCD and let its fourth vertex be D(a, b).

Join AC and BD. Let AC and BD intersect at point O.

We have known that the diagonals of a parallelogram bisect each other.

So, O would be the midpoint of AC as well as that of BD.

$A\left(0,\:0\right)=\left(x_1,\:x_2\:\right)$

$C\left(10,\:4\right)=\left(x_2,\:x_2\:\right)$

The midpoint of AC is:

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$

$\left(x_1,\:y_1\right)=\left(0,\:0\right),\:\left(x_2,\:y_2\right)=\left(10,\:4\right)$

$=\left(\frac{10+0}{2},\:\frac{4+0}{2}\right)$

$=\left(5,\:2\right)$

The midpoint of BD is:

$=\left(\frac{a+2}{2},\:\frac{b+4}{2}\right)$

so

∵ $\frac{a+2}{2}=5$

$a+2=10$

$a=8$

∵ $\frac{b+4}{2}=2$

$b+4=4$

$b=0$

Hence, the fourth vertex is D(8, 0)

4 0

3 years ago

What is 69,000 rounded to the nearest hundred

Yuliya22 [10]

The answer would still be 69,000

Hope this Helps

4 0

3 years ago

Read 2 more answers

(5x+3y=-3<br> | 3x – 3y =-21

disa [49]

Answer:

8x = -24 => x = -3

y = 4

Step-by-step explanation:

7 0

3 years ago

What is the rule for dilations

padilas [110]

Size change for preimage...

7 0

3 years ago

John stands 150 meters from a water tower and sights the top at an angle of elevation of 36º. If John's eyes are 2 meters above

horsena [70]

Answer:

The height of tower $DB=111\ meters$ .

Step-by-step explanation:

Diagram of the given scenario is shown below.

Given that,

Distance between John and tower is $CE=150 \ meters$ .

Angle of elevation to the top of the tower is $\angle DEC=36$ °.

Height of John is $CB=2\ meters$ .

To Find: Height of the tower $DB$ .

So,

In triangle ΔDCE,

$Tan$ (∠ $DEC)= \frac{DC}{CE}$

$Tan (36)= \frac{DC}{150}$

$DC= tan(36)\times 150$

$DC=108.98\ meters$

Now,

To calculate the height of tower we have

$DB=DC+CB$

$DB=108.98+2$

$DB=110.98\ meters$ ≈ $111 \ meters$

Therefore,

The height of tower $DB=111\ meters$ .

6 0

3 years ago