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Shtirlitz [24]
4 years ago
10

Is 4.0 27 greater than or less than 4.00 92?

Mathematics
2 answers:
Morgarella [4.7K]4 years ago
8 0
Isnt it less ? Correct me if im wrong
Lisa [10]4 years ago
7 0
4.027 and 4.0092

Look at the decimal places. There is a 2 in the hundredths place in 4.027, and a 0 in the hundredths place in 4.0092.

4.027 is greater than 4.0092 because if you keep going down each decimal place, the numbers are the same until you get to the hundredths place -- where you will see the 2 is greater than 0.
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A school concert has students tickets for $7 and nonstudents tickets for $12. If the school made $1973 selling 214 tickets? How
bearhunter [10]

Answer:

119 student tickets and 95 non-student tickets

Step-by-step explanation:

I did a trial-and-error solution.

I started with 107 students and 107 non-students:

(107*$7)+(107*$12) = $2033

It was too high, which tells us that there should be more who paid for the cheaper price.

I ended up with 119 and 95:

(119*$7)+(95*$12) = $1973

8 0
3 years ago
Read 2 more answers
The ages of max and his father add up to 35 years. Max's father's age is the same as five more than the square of max's age
34kurt
M+f=35
f=5+m^2
sub 5+m^2 for f
m+5+m^2=35
m^2+m+5=35
minus 35 both sides
m^2+m-30=0
factor
what 2 numbers mulitply to get -30 and add to get 1
-5 and 6
(m-5)(m+6)=0
set to zto
m-5=0
m=5

m+6=0
m=-6
age can't be negative

max is 5
father is 30
5 0
3 years ago
Interpret the interval. We are 95% confident that the true average blood lead level for male workers is greater than that of fem
Usimov [2.4K]

Answer:

Step-by-step explanation:

There are key notes here

- *95% confidence or 95% confidence interval*

This is a popular percentage used in finding a statistic (a statistic is a parameter or measure which has values). A 95% confidence interval for a parameter is a wide range of values within which the specific value of the statistic you're testing should lie or does lie. Remember that a range is an interval from a certain value to a higher value e.g. a range of/from (8 - 18). If the parameter you're testing is the mean (the numerical average of a group) for example and that is your range then it means that you are 95% certain (almost completely or almost 100% certain) that the population mean lies within that interval. In the case of this question, there are no numerical values for the mean (average)

- *true average*

True average means the true mean value for the population

- *an amount within the confidence interval*

In this case, we're comparing the mean/average for male workers and female workers so DIFFERENCE IN MEANS is the actual statistic we are looking at here. So, for (A)

(A) We are 95% confident that the difference in mean of blood lead level in male workers and female workers is an amount or value that lies within the confidence interval created

(B) Same as (A) above BUT here, we're testing that (our hypothesis is) the true mean blood lead level for male workers is LESS THAN that of female workers.

(C) If a conclusion cannot be drawn from the statistical information given, that means we can't find an accurate cause-and-effect relationship between the independent variable(s) and dependent variable(s)

(D) Here, our hypothesis (what we are testing or what we seek to know) is whether the true mean blood lead level for male workers is GREATER THAN that of female workers. Next, we are using a 95% confidence interval. Now, the DIFFERENCE IN MEANS which is what we are measuring falls outside the confidence interval created. This means that the actual value of the difference in means is either less than the lower boundary value in our confidence interval OR higher than the upper boundary value in our confidence interval.

5 0
3 years ago
Find m∠A given ΔABC where a=4, b=6, c=3.
igomit [66]
For this question, we're going to use the law of cosines.
The law of cosines is the following equation:

a^2=b^2+c^2-2(b)(c) \cos(A)

We know the values of a, b, and c. We want to find the measure of angle A.
a=4
b=6
c=3

Now, plug in these values into the equation.

4^2=6^2+3^2-2(3)(6) \cos(A)
16=45-36 \cos(A)

Add both sides by 36 \cos(A) and subtract both sides by 16

36 \cos(A)=29

Divide both sides by 36

\cos(A)= \dfrac{29}{36}

Take the inverse cosine, or arc cosine, of both sides.
Using a calculator, you'll get the following result.

A \approx 36.3^O

The measure of angle A should be 36.3 degrees. Hope this helps! :)
4 0
3 years ago
What pie 3.14 saqured
kondaur [170]

Answer:

9.8596

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
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