Question

beginning at sea level a scuba diver dove 1 2/3 feet into the water , and then dove an additional 3 2/5 feet at what elevation is the scuba diver

Answer 1

The given details are illustrations of addition and subtractions of fractions.  The scuba driver is at an elevation of $-5\frac{1}{15}$ ft below the sea  level.

Given that:

$n_1 = 1\frac 23$ --- the first dive

$n_2 = 3\frac 25$ ---- the additional dive

From the question, we understand that the diver starts at the sea level.

This is represented with 0ft.

So, the diver's elevation (d) is calculated as follows:

$d = 0 - n_1 - n_2$ --- we use subtraction because the diver is below the sea level

So, we have:

$d = 0 - 1\frac 23 - 3\frac 25$

$d = - 1\frac 23 - 3\frac 25$

Convert fractions

$d = - \frac 53 - \frac{17}5$

Take LCM

$d = \frac{-5 \times 5 - 17 \times 3}{15}$

$d = \frac{-76}{15}$

Reduce fraction

$d = -5\frac{1}{15}$

The above value means that the diver's elevation is at $-5\frac{1}{15}$ ft below the sea  level.

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