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3 years ago

What focal-length eyepiece is needed if your eye can resolve objects 0.10 mm apart at a distance of 25 cm?

Mathematics

1 answer:

Kay [80]3 years ago

7 0

M=d/f so, f=d/M f=25/.01. =2500cm

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4x-10=30<br> 2n-7=30 <br> S/3+2=4

emmasim [6.3K]

Answer:

x=10 n=18.5 s=6

Step-by-step explanation:

4x-10=30

Add 10 to both sides

4x-10+10=30+10

4x=40

Divide by 4 on both sides

(4x)/4=40/4

x=10

2n-7=30

Add 7 to both sides

2n-7+7=30+7

2n=37

Divide by 2 on both sides

(2n)/2=37/2

n=18.5

(s/3)+2=4

Subtract 2 from both sides

(s/3)+2-2=4-2

(s/3)=2

Multiply by 3 on both sides

3s/3=2*3

s=6

6 0

3 years ago

Use the equation below to find y, if m= 8 and x=6.<br> y=mx <br> y=?

Lunna [17]

Answer:

The value of y is 48.

Step-by-step explanation:

You have to substitute the values into the equation :

$y = mx$

$let \: m = 8,x = 6$

$y = 8 \times 6$

$y = 48$

8 0

2 years ago

Read 2 more answers

Pls help me for brainliest answer

Ket [755]

Answer with Step-by-step explanation:

$a)3n + 4 \\ \\n = 1 \\ 3 \times 1 + 4 \\ 3 + 4 \\ =7 \\ \\ n = 2 \\ 3 \times 2 + 4 \\ 6 + 4 \\ = 10 \\ \\ n = 3 \\ 3 \times 3 + 4 \\ 9 + 4 \\ = 13 \\ \\ n = 4 \\ 3 \times 4 + 4 \\ 12 + 4 \\ = 16 \\ \\ n = 10 \\ 3 \times 10 + 4 \\ 30 + 4 \\ = 34 \\$

So in this sequence,

1st term = 7

2nd term = 10

3rd term = 13

4th term = 16

10th term = 34

$b)4n - 5 \\ \\ n = 1 \\ 4 \times 1 - 5 \\ 4 - 5 \\ = - 1 \\ \\ n = 2 \\ 4 \times 2 - 5 \\ 8 - 5 \\ = 3 \\ \\ n = 3 \\ 4 \times 3 - 5 \\ 12 - 5 \\ = 7 \\ \\ n = 4 \\ 4 \times 4 - 5 \\ 16- 5 \\ = 11 \\ \\ n = 10 \\ 4 \times 10 - 5 \\ 40 - 5 \\ = 35$