All categories

3 years ago

Which of these is usually true of a convenience sample?

Mathematics

2 answers:

nika2105 [10]3 years ago

5 0

Answer: it is unrepresentative of larger group

APEX ANSWER - prob and stats

Digiron [165]3 years ago

3 0

A is usually true.

A convenience sample does not always represent the entire population and is not always random; therefore it does not always give reliable results. It does allow for people with stronger opinions to participate, however, so A is true.

You might be interested in

mhairi invest 1000 for 5 years at 4% compound interest p.a calculate how much interest she has gained over the 5 years

KiRa [710]

Answer:

Step-by-step explanation:

$1000×1.04⁵ ≅ $1216.65

interest ≅ $216.65

5 0

3 years ago

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

5j+s=t-2 solve for t

Gekata [30.6K]

The answer is

T= 5j+s+2

4 0

3 years ago

Read 2 more answers

Millie borrowed $20 from her dad. Explain why this situation indicates a negative number for Millie even though $20 is a positiv

Nata [24]

Millie will have to pay the $20 back, and as she already has no money, she's now $20 in debt

7 0

3 years ago

Read 2 more answers

Are the following expressions equivalent?

DaniilM [7]

12x +13 equal to or not equal to 12x - 6 + 8 or 12x +2

No, these expressions are not equivalent.
Hope this helps!

3 0

3 years ago

Read 2 more answers