Answer:
following are the solution to the given points:
Step-by-step explanation:
In point a:


calculating unit vector:

the point Q is at a distance h from P(6,6) Here, h=0.1

the value of Q= (5.92928 ,6.07071 )
In point b:
Calculating the directional derivative of
at P in the direction of 



In point C:
Computing the directional derivative using the partial derivatives of f.

The capacity of the mug is 7/6 cups.
<h3>
What is the capacity of the mug?</h3>
Given,
A mug is 3/7 full.
The mug contains 1/2 of a cup of water.
Solution:
Let x be the water.
Water the mug has = 3/7 of x
= 3/7x
Since the water in the mug is 1/2 cup,
3/7x = 1/2
x = 1/2 ÷ 3/7
= 1/2 × 7/3
= 7/6
Therefore,
The capacity of the mug is 7/6 cups.
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Answer:
(15,-14)
Step-by-step explanation:
Given that,
The midpoint of FG is (6-4) and the corrdinates of F are (-3,6).
Let (x,y) be the coordinates of point G. Using mid point formula,

So, the coordinates of G are (15,-14).
Let 'w' represent the width of the parking lot, then 'w+6' represents its length
area = width * length
160 = w * (w+6)
solving for 'w' we have a positive value of w=10
10+6=16
the width of the parking lot is 10 yards, the length of the parking lot is 16 yards