Answer:
D. (-2, -6) and (5,15)
Step-by-step explanation:
When you set the equations together, you get x^2-3x-10. You then set this equation equal to zero and get (x-5)(x+2) or x=-2 and x=5. Then, plug these x-values into each equation to get your y-values.
Answer:
<h3>
9, 11, 13, 15</h3>
Step-by-step explanation:
{k - some integer}
2k+1 - the first odd integer (the least)
5(2k+1) - five times the least
5(2k+1)+3 -<u> three more than five times the least</u>
2k+1+2 = 2k+3 - the odd integer consecutive to 2k+1
2k+3+2 = 2k+5 - the next odd consecutive integer (third)
2k+5+2 = 2k+7 - the last odd consecutive integer (fourth)
2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>
2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3
8k + 16 = 10k + 5 + 3
- 10k -10k
-2k + 16 = 8
-16 - 16
-2k = -8
÷(-2) ÷(-2)
k = 4
2k+1 = 2•4+1 = 9
2k+3 = 2•4+3 = 11
2k+5 = 2•4+5 = 13
2k+7 = 2•4+7 = 15
Check: 9+11+13+15 = 48; 48-3 = 45; 45:5 = 9 = 2k+1
Answer: Option 'D' is correct.
Step-by-step explanation:
I need to borrow some money from my parents as my deficit has <u>grown or increased.</u>
If deficit of any individual increases , means, he is short of money.
So, he needs to borrow from his parents.
Hence, Option 'D' is correct.
Ok so to solve this problem we're going to need to find out how much money they made (their revenue) and the subtract the cost of paying the employees.
So, let's start by finding their revenue
Step 1: Multiply the cost of each beverage by the number sold
Coffees: 20 x 2.85 = 57
Lattes: 17 x 4.80 = 81.6
Step 2: add up the money made from the coffees and the money made from the lattes to get the total revenue
57 + 81.6 = 138.6
So the shop made $138.60 on Tuesday. Let's set that aside while we find out how much the shop's costs were.
Step 3: Find the price of paying two employees for 6 hours
2 x 6 x 14.5 = 174
So the shop had to pay the employees $174.00 for working there.
Step 4: Find the overall profit/loss by subtracting the cost from the revenue
138.6 - 174 = -35.4
So the shop had a loss of $35.40 on Tuesday.
Hope that helps! Feel free to leave a comment or send me a message if I can clarify anything :)
While I cannot see your answer choices, the correct answer would be one that has a coefficient that is a multiple of 3 and has an x raised to an exponent of no more than 2. It could have any other variables in it.
The reason this has to be is because of the GCF. Since 3 is part of the GCF, and the other monomial has a coefficient of 3, this means the missing monomial must be divisible by 3 as well.
Since x² is part of the GCF, the missing monomial must contain x². However, if it were to contain x³ or anything larger, the GCF would have x with a higher exponent.
