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nexus9112 [7]
3 years ago
6

How many 3-digit numbers can be formed using the digits 1, 2, 3, 4, 5, 6, 7 if repetition of digits is not allowed?

Mathematics
1 answer:
attashe74 [19]3 years ago
7 0
Think of it this way:
_ _ _ (3 digit number)

for the first blank you could have 7 possibilities
for the second blank you could have 6 possibilities
for the third blank you could have 5 possibilities
because each time you fill in a blank one number is removed from the list of possibilities

7×6×5=210. there are 210 possibilities
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It cost $50 a month


Work: 700 - 100 = 600

600 / 12 = 50


Hope this helps!

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3 years ago
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Write 48 ten thousands, 21 hundreds, and 7 tens in word form and expanded form.
stira [4]

Answer:

48,217 maybe idk

Step-by-step explanation:

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Use order of operation
Inessa [10]
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3 years ago
What is the answer i need answers now
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The answer is 10/3. Because you have 3 wholes and 1/3 so, 3x3 is 9 and you still have the extra 1 so 9+1=10 therefore your answer would be 10/3
5 0
1 year ago
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If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.
solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

WX=\sqrt{(-3-(-10))^2+(-1-4)^2}

WX=\sqrt{(-3+10)^2+(-5)^2}

WX=\sqrt{(7)^2+(-5)^2}

WX=\sqrt49+25}

WX=\sqrt{74}

Similarly,

XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}

WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}

Now,

WX=WY

So, triangle is an isosceles triangles.

and,

WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2

WX^2+WY^2=74+74

WX^2+WY^2=148

WX^2+WY^2=(2\sqrt{37})^2

WX^2+WY^2=WY^2

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0
2 years ago
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