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Romashka-Z-Leto [24]

3 years ago

10

State the slope of the line. A:undefined B:1 C:-2 D:0 Help ASAP

2 answers:

Nikitich [7]3 years ago

8 0

Every point on this line has the same y coordinate, which is -2. There is no "rise" at all so rise = 0 while the "run" is any nonzero value you want. If you made the run be say 2, then

slope = rise/run = 0/2 = 0

The slope is 0

Answer: D) 0

note: all horizontal lines like this have a slope of 0. It doesn't matter what the y intercept is

Oksanka [162]3 years ago

8 0

Slope addresses how steep the line is. Since the line is flat, it neither slants up or down. Therefore, there is not slope or slant, thus the slope is 0. There is a nonexistent change in the y-axis, but a change in the x-axis.

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See below

Step-by-step explanation:

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3 years ago

Given that OA = 2x + 9y, OB = 4x + 8y and CD = 4x - 2y, explain the geometrical relationships between the straight lines AB and

Step2247 [10]

Answer:

The geometrical relationships between the straight lines AB and CD is that they have the same slope

Step-by-step explanation:

Given

$OA = 2x + 9y$

$OB = 4x + 8y$

$CD = 4x - 2y$

Required

The relationship between AB, CD

Since AB is a straight line and O is the origin, then:

$AB = (c - a)x + (d - b)y$

Where:

$OA = ax + by$ ====> $OA = 2x + 9y$

$OB = cx + dy$ ====> $OB = 4x + 8y$

This implies that:

$a =2$ $b = 9$ $c = 4$ $d = 8$

So:

$AB = (c - a)x + (d - b)y$

$AB = (4 - 2)x + (8 - 9)y$

$AB = 2x -y$

So, we have:

$AB = 2x -y$

$CD = 4x - 2y$

Calculate the slope (m) of $AB\ and\ CD$

$m = \frac{Coefficient\ of\ y}{Coefficient\ of\ y}$

For AB

$m_1 = \frac{-1}{2}$

$m_1 = -\frac{1}{2}$

For CD

$m_2 = \frac{-2}{4}$

$m_2 = \frac{-1}{2}$

$m_2 = -\frac{1}{2}$

By comparison:

$m_1 = m_2 = -\frac{1}{2}$

This implies that both lines have the same slope

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3 years ago