1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Goryan [66]
3 years ago
8

What is the amplitude of the function shown in the graph​

Mathematics
1 answer:
Pie3 years ago
7 0

Answer:

2

Step-by-step explanation:

amplitude=\frac{1}{2}(0.5-(-3.5))=2

You might be interested in
2. Given a directed line segment with endpoints A(3, 2) and B(6, 11), what is the point that
KATRIN_1 [288]

Answer:

The point of division is (5 , 8)

Step-by-step explanation:

* Lets explain how to solve the problem

- If point (x , y) divides the line whose endpoints are (x_{1},y_{1})

 and (x_{2},y_{2}) at ratio m_{1}:m_{2} , then

 x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}} and

 y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

* Lets solve the problem

- The directed line segment with endpoints A (3 , 2) and B (6 , 11)

- There is a point divides AB two-thirds from A to B

∵ The coordinates of the endpoints of the directed line segments

   are A = (3 , 2) and B = (6 , 11)

∴ (x_{1},y_{1}) is (3 , 2)

∴ (x_{2},y_{2}) is (6 , 11)

∵ Point (x , y) divides AB two-thirds from A to B

- That means the distance from A to the point (x , y) is 2/3 from

  the distance of the line AB, and the distance from the point (x , y)

  to point B is 1/3 from the distance of the line AB

∴ m_{1}:m_{2} = 2 : 1

∵ x=\frac{(3)(1)+(6)(2)}{2+1}=\frac{3+12}{3}=\frac{15}{3}=5

∴ The x-coordinate of the point of division is 5

∵ y=\frac{(2)(1)+(11)(2)}{2+1}=\frac{2+22}{3}=\frac{24}{3}=8

∴ The y-coordinate of the point of division is 8

∴ The point of division is (5 , 8)

6 0
3 years ago
Natasha wants to find out if the neighborhood supports lowering the speed limit on the street in front of her school. Which is a
Daniel [21]
The answer is
Thirty residents who live within a 2 mile radius of natashas school.
8 0
2 years ago
Sasha can run at an average speed of 934 9 3 4 min/mi. She runs at this speed for 6814 68 1 4 min. How many miles does Sasha run
lutik1710 [3]
I don't know what the spaces are meant for but I think that means 934 and 6814 only. Another point is, speed should be expressed in units of distance over time. So that would be miles/min.

So, distance could be calculated by multiplying speed and time.

d = 934 mi/min * 6814 min
d = 6,364,276 miles


8 0
3 years ago
Maria charges $15 for 3 h of babysitting. How much does Maria charge for 5 h of babysitting?
anzhelika [568]

Answer:

25 I think             hope this helped

5 0
3 years ago
Read 2 more answers
Solve the exponential equation for x<br> 64^7x-8 = 1
SOVA2 [1]

X=9/64^7

Hope this helps

7 0
3 years ago
Read 2 more answers
Other questions:
  • The relation that is represented by the equation y = 45 – 3x has the domain {5, 7, 9, 11}. Which of the following sets is the ra
    8·1 answer
  • What is the Divisor for equivalent fraction ?<br> 4/12=1/3
    15·1 answer
  • Your friend incorrectly says the solution to the equation 11.2y - 7.4y=141.36 is y=7.6 what error did your friend make?
    10·2 answers
  • Ted is asked to multiply 10 to the second power x 18.72. How Should he move the decimal point
    8·1 answer
  • PLEASE HELP URGENT multiple choice algebra question:
    15·1 answer
  • I need to know how to answer this if someone could explain it step by step thanks!
    5·1 answer
  • If the ratio of boys to girls is 1:4 and there are 20 girls in your class, how many boys are there?
    15·2 answers
  • Who is more likely to run into problems using a credit card..
    9·1 answer
  • The domain of a transformation function that reflects coordinates over the y-axis consists of the coordinates
    6·1 answer
  • John must mount a box which is 12 5/8 inches wide. He wants to leave 7 1/2 inches on each side of the
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!