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Debora [2.8K]
4 years ago
12

An ordinary 52-card deck is thoroughly shuffled. You are dealt four cards. (a) What is the probability that all four cards are s

evens. (b) What is the probability that at least one of the cards is a seven. (c) What is the probability that none of them are seven. (d) What is the probability that two out the four cards is a seven
Mathematics
1 answer:
dusya [7]4 years ago
3 0

Answer:

a) The probability of getting a seven is 4/52

b) At least one of the cards is a seven=0.2813

c) The probability that none of them are seven=  0.7187

d) The probability that two out the four cards is a seven= 0.043

Step-by-step explanation:

A deck contains 52 cards containing 4 sets of 13 cards . Each set has a seven card in it. Thus there are 4 seven cards in a deck of 52 cards.

a) The probability of getting a seven is 4/52=0.0769

b) At least one of the cards is a seven=

1- P(no seven)

= 1- 4C0 * 48C4/ 52C4= 1- 0.7187= 0.2813

c) The probability that none of them are seven=4C0 * 48C4/ 52C4=  0.7187

d) The probability that two out the four cards is a seven= First card is seven * second Card is seven * two cards are not seven

= 4/52* 3/51*48/50= 0.0769*0.0588*0.96= 0.043

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