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3 years ago

1/4+(-1/3)•1/2 what’s the answer to this math problem

Mathematics

1 answer:

Julli [10]3 years ago

6 0

Answer:

0.08333333... or 0.0834

Step-by-step explanation:

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A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?

seraphim [82]

Answer:

$P\left(E\right)=\frac{55}{1024}$

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

$nCr=\frac{n!}{r!\left(n-r\right)!}$

Plug in n = 12 and r = 9

$=\frac{12!}{9!\left(12-9\right)!}$

$=\frac{12!}{9!\cdot \:3!}$

$=\frac{12\cdot \:11\cdot \:10}{3!}$ ∵ $\frac{12!}{9!}=12\cdot \:11\cdot \:10$

$=\frac{1320}{6}$ ∵ $3!\:=\:3\times 2\times 1=6$

$=220$

Thus, the probability will be:

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}$

$=\frac{220}{4096}$

$=\frac{55}{1024}$

Thus, the probability of the coin landing tails up exactly nine times will be:

$P\left(E\right)=\frac{55}{1024}$

4 0

3 years ago

Whats does 9+10 equal to?

Ymorist [56]

19 is the answer for this question

7 0

3 years ago

Can someone help me please

xeze [42]

9514 1404 393

Answer:

slope = 1

Step-by-step explanation:

In the attachment, we have shown rise and run as 3 units each. The segments could be drawn 1 unit long. In any event, the ratio is the slope:

slope = rise/run = 3/3

slope = 1

_____

It is most convenient to draw the rise and run segments from/to places where the line crosses grid intersections. Often, but not always, the y-intercept will be such a point. Then you can look for the nearest grid crossing for figuring rise and run.

Here, the y-intercept is (0, 1), and the closest grid crossing to the right is (1, 2). The rise is 2-1 = 1, and the run is 1-0 = 1. The ratio is 1/1 = 1, same as above. The ratio of rise to run will be the same everywhere for a straight line.