Please help me! Im making the first correct answer brainliest!

Mathematics

1 answer:

masha68 [24]2 years ago

7 0

Answer:

You didn't ask a question.

Step-by-step explanation:

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X ⋅ x = ? (1 point) jjjj

liraira [26]

Answer:

x-x = 0

x+x= 2x

x×x= x^2

have a nice day...

4 0

2 years ago

Using the graph as your guide, complete the following statement.

ollegr [7]

Answer:

positive

Step-by-step explanation:

the discriminant of the function is postive.

because from the graph we notice that it has 2 intercepts on x-axis, which means the function has 2 real solution when y=0

that implies the discriminant is positive.

$\Delta = \sqrt{b^2-4ac}$

if $\Delta > 0$ we have 2 distinct real solution

if $\Delta$ we have no real solution but 2 complex solutions

if $\Delta = 0$ we have 2 identical real solution

7 0

3 years ago

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have