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3 years ago

Write four numbers that round to 700,000 when rounded to the nearest hundred thousand

2 answers:

6 0

699,512
655,456
689,433
701,001 this is the correct answer and btw i copied this from my e-notes and i own the rights to those

miskamm [114]3 years ago

4 0

699,548
655,417
689,414
701,000

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A test consists of 10 multiple choice questions, each with five possible answers, one of which is correct. To pass the test a st

Softa [21]

Answer:

0.006369

Step-by-step explanation:

Given that a test consists of 10 multiple choice questions, each with five possible answers, one of which is correct.

By mere guessing p = probability for a right answer = 1/5 =0.20

There are two outcomes and each question is independent of the other.

X no of questions right is Bin (10,0.20)

the probability that the student will pass the test

= prob of getting more than 60%

= $P(X\geq 6)$

=0.006369

8 0

3 years ago

On the function machine shown below, the function rule is given as a variable expression. When the output is 99, what is the inp

beks73 [17]

Answer: option d.

Step-by-step explanation:

We have the function:

y = f(x) = x^2 - 1

The output is 99 when y = 99, and the input is x.

Then we need to solve:

y = 99 = x^2 - 1

for x.

99 = x^2 - 1

99 + 1 =x^2

100 = x^2

√100 = x

10 = x

The correct option is d, input equals 10.

7 0

2 years ago

37:35-(32:24-10).2+√289=

Mkey [24]

Answer:

to simplify this it is 1295/1804

Step-by-step explanation:

3 0

2 years ago

Consider the following equations x=4/t and y = 4-t^2 a. Solve the equation for y (eliminate the parameter.)

Nookie1986 [14]

Answer:

y=-16^a/x^2 + 4

Step-by-step explanation:

3 0

3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

3 years ago

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