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zhuklara [117]
3 years ago
10

The perimeter of a triangle is 7a-11b. If two of its sides are 2a+b and a-9b, what is the third side?

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0
You subtract the  2 given sides from the perimeter so its

7a - 11b - (2a + b) - (a - 9b)    ( Note the 2 sides must be in parantheses)

= 7a - 11b - 2a - b - a + 9b 

adding like terms:-

= 4a - 3b
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<em>Given</em><em>,</em>

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<em>=</em><em> </em><em>4</em><em>c</em><em> </em><em>-</em><em> </em><em>3</em><em>2</em><em> </em><em>-</em><em> </em><em>(</em><em> </em><em>3</em><em>c</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>)</em>

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