Answer:
3/8
Step-by-step explanation
Convert 3/4 to 6/8 to make it easier subract since this problem asks how much he has left.
So 6/8-3/8=3/8
Aplicando multiplicación cruzada, tiene-se que el valor de w es w = 9.
- Cuando una proporción es dada, con una igualdade de duas proporciones, puede-se aplicar multiplicación cruzada entre ellas.
En este problema, la ecuación que relaciona las proporciones es dada por:

Aplicando multiplicación cruzada:




El valor de w es w = 9.
Un problema similar es dado en brainly.com/question/24615636
Answer:
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Step-by-step explanation:
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Answer:
Graph C
Step-by-step explanation:
Proof by induction
Base case:
n=1: 1*2*3=6 is obviously divisible by six.
Assumption: For every n>1 n(n+1)(n+2) is divisible by 6.
For n+1:
(n+1)(n+2)(n+3)=
(n(n+1)(n+2)+3(n+1)(n+2))
We have assumed that n(n+1)(n+2) is divisble by 6.
We now only need to prove that 3(n+1)(n+2) is divisible by 6.
If 3(n+1)(n+2) is divisible by 6, then (n+1)(n+2) must be divisible by 2.
The "cool" part about this proof.
Since n is a natural number greater than 1 we can say the following:
If n is an odd number, then n+1 is even, then n+1 is divisible by 2 thus (n+1)(n+2) is divisible by 2,so we have proved what we wanted.
If n is an even number" then n+2 is even, then n+1 is divisible by 2 thus (n+1)(n+2) is divisible by 2,so we have proved what we wanted.
Therefore by using the method of mathematical induction we proved that for every natural number n, n(n+1)(n+2) is divisible by 6. QED.