Answer:
\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]
Step-by-step explanation:
Given is a matrix 3x3 as
![\left[\begin{array}{ccc}1&0&2\\-3&1&4\\2&-3&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%262%5C%5C-3%261%264%5C%5C2%26-3%264%5Cend%7Barray%7D%5Cright%5D)
|A| =2 hence inverse exists.
Cofactors are 16 20 7
6 8 3
2 2 1
Hence inverse =
![\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%266%262%5C%5C20%268%262%5C%5C7%263%261%5Cend%7Barray%7D%5Cright%5D)
Suppose you have 192
marbles.
You want to group this marble into 15 groups.
What we need to do is simply divide the given numbers
=> 192 is our dividend and 15 is our divisor
=> 192 / 15
=> 12.8 , thus there are 12 groups with a remainder of 8.
Now, convert this into fraction
=> 12 is our quotient, 8 is our remainder to use as our numerator and
192 as our denominator.
thus the fraction value of this is :
=> 12 8/192
Answer:
chocolate bar - 1 (whole number)
Step-by-step explanation:


so I switch it become
