Answer:
7/8 > 5/6
Step-by-step explanation:
Well look at it this way: 7/8 needs 1 more eighth until 1. 5/6 needs one more sixth until one. One eighth is smaller, so it requires a smaller amount to get to a greater number, if that makes sense. So 7/8 is greater than 5/6.
A.Fractions and decimals are not integers<span>. All whole </span>numbers<span> are</span>integers<span> (and all natural </span>numbers<span> are </span>integers<span>), but not all </span>integers<span>are whole </span>numbers<span> or natural </span>numbers<span>. For example, -5 is an </span>integer<span>but not a whole </span>number<span> or a natural </span>number<span>.
B.</span><span>A </span>number<span> is </span>rational<span> if it can be represented as p q with p , q ∈ Z and q ≠ </span>0<span> . Any </span>number<span> which doesn't fulfill the above conditions is irrational. It can be represented as a ratio of two integers as well as ratio of itself and an irrational </span>number<span> such that </span>zero<span> is not dividend in any case
</span>C.<span>In mathematics, an </span>irrational number<span> is any </span>real number<span> that cannot be expressed as a ratio of integers. </span>Irrational numbers<span> cannot be represented as terminating or repeating decimals.
</span>D.<span>The correct answer is </span>rational<span> and </span>real numbers<span>, because all </span>rational numbers<span> are also </span>real<span>. Correct. The </span>number<span> is between integers, so it can't be an integer or a whole </span>number<span>. It's written as a ratio of two integers, so it's a </span>rational number<span> and not irrational.
</span> Witch one do u think it is??
Answer:
1 and 2 are not polyhedrons, as a circle has infinite sides
1. cone, 1 vertex
2. sphere, nothing
3. pentagonal prism?
wait but can't every face be a base???
anyway 7 faces, 10 vertices
4. triangular prism
5 faces, 6 vertices
Step-by-step explanation:
Answer:
-7/2 or -3.5
Step-by-step explanation:
Make the equation first
7x-1 = 5x-8
7 = -2x
-7/2 = x
Answer:
do you have any options for this question just to check??
