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LuckyWell [14K]
3 years ago
7

Solve -2x+3=2x+3 and is it no, one or many solutions​

Mathematics
2 answers:
MrRissso [65]3 years ago
5 0

Answer:

One Solution

Step-by-step explanation:

-2x+3=2x+3

-2x+3-3=2x+3-3

-2x=2x

-2x-2x=2x-2x

-4x=0

\frac{-4x}{-4}=\frac{0}{-4}

x=0

Ivanshal [37]3 years ago
5 0

Answer: 0

Step-by-step explanation:

-2x+3=2x+3

-2x+3-3=2x+3-3

-2x=2x

-2x-2x=2x-2x

-4x=0

Therefor, the answer is 0.

x=0

* Hopefully this helps:) Mark me the brainliest:)!!!

<em>∞ 234483279c20∞</em>

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Solve this and get 12 points
Pachacha [2.7K]

Answer:

9

Step-by-step explanation:

First, find <em>x</em>. Since <em>x</em> is the average of the three number, add the three up and then divided by three. Thus:

x=\frac{13+-16+6}{3}=3/3=1

<em>y</em> is the cube root of 8. Thus:

y=\sqrt[3]{8}=2

So:

x^2+y^3\\=(1)^2+(2)^3\\=1+8=9

5 0
3 years ago
Read 2 more answers
Which value of m will create a system of parallel lines with no solution?
Pepsi [2]
Rearranging y = 8x -4y = 12 in the y = mx + b form gives y = 2x - 3

y = 2x - 3

y = mx - 6 (already in y = mx + b form)

--------------

Parallel lines have the same slope.

m = 2

Note that the two lines have the different y-intercepts and are not the same line.
3 0
3 years ago
Read 2 more answers
2/3xd=10/9 what is d
lisabon 2012 [21]

Answer:d=5/3x

Step-by-step explanation:

Let's solve for d.

(2/3x)(d)=10/9

Step 1: Divide both sides by (2x)/3.

2/3dx / 2x/3=10/9 / 2x/3

d=5/3x

8 0
3 years ago
Use​ Gauss's approach to find the following sums​ (do not use​ formulas). 1+3+5+7+...999
muminat
S=1+3+5+\cdots+995+997+999
S=999+997+995+\cdots+5+3+1
\implies 2S=(1+999)+(3+997)+(5+995)+\cdots+(995+5)+(997+3)+(999+1)

2S=\underbrace{1000+1000+\cdots+1000+1000}_{500\text{ times}}

(We are adding 500 instances of 1000 because that's how many odd numbers there are between 1 and 1000, inclusive.)

2S=500\times1000=500000
\implies S=250000
4 0
3 years ago
It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i
USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 55, \pi = \frac{24}{55} = 0.4364

93% confidence level

So \alpha = 0.07, z is the value of Z that has a pvalue of 1 - \frac{0.07}{2} = 0.965, so Z = 1.81.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0
3 years ago
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