Solve -2x+3=2x+3 and is it no, one or many solutions
2 answers:
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Answer:
The patient owe $1255.6 .
Step-by-step explanation:
As given
A patient's total surgery charges are $1,278.
The patient must pay the annual deductible of $1,000.
The policy states a 80-20 coinsurance. (i.e 20% of the surgery amount is given by the patient .)
20% is written in the decimal form .
= 0.20
20% of patients surgery cost = 0.20 × $1278
= $ 255.6
Patients owe = Deductible cost + 20% of patients surgery cost
= $1000 + $255.6
= $ 1255.6
Therefore the patient owe $1255.6 .
Answer:
(B) The magnitude is 7sqrt2, and the direction angle is approximately 135 degrees.
Step-by-step explanation:
From the figure, the coordinate of the tail of the vector,
The coordinate of the head of the vector,
The magnitude of a vector is the length between the head and tail of the vector.
By using the distance formula,
the magnitude of the vector
Now, let be the angle made by the vector with the positive direction of the x-axis, so
So, the magnitude of the vector is which makes
with the positive direction of the x-axis.
Hence, option (B) is correct.
Answer:
a. X~N(2,885, 651)
b. 0.086291
c. 0.00058
d. 3213.10 calories
Step-by-step explanation:
a. -A normal distribution is expressed in the form X~N(mean, standard deviation).
-Let X a random variable denoting the number of calories consumed.
-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.
-This distribution is expressed as X~N(2,885, 651)
b. The probability that less than 2000 calories are consumed is calculated using the formula:
#substitute the given values in the formula to solve for P:
Hence, the probability of consuming less than 2000 calories is 0.08691
c. The proportion of customers consuming more than 5000 calories is calculated as:
Hence, the proportion of customers consuming over 5000 calories is 0.00058
d. The least amount of calories to get the award is calculated as:
1% is equivalent to a z value of 0.50399.
-We equate this to the formula to solve for the mean consumption:
Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.