I did this. The table would be this one D=P-2.50
Answer:
14,062.5ft^2
Step-by-step explanation:
A farmer has a given length of fencing. Since this fencing is used to enclose a rectangular area, before it is then divided it into four pens using the same provided fencing material. This will definitely lead to five lengths of fencing which come along one side of the rectangle to form four pens.
Let us assume that the length of the each of the five sides be xft.
Then let the length of each of the two sides in the be yft.
Since the total length of fencing available is 750 feet.
Then we can have an equation of such:
5x+2y=750
Making y the subject
2y = 750-5x
y = 750-5x/2. ........1
The area of the rectangular region is given by:
A = xy. ......... 2
Combining (1) in (2) to find the area
A(x)= x. (750−5x)/2
=750x−5x^2/2 ........... (*)
Going by the means of first diffential calculus.
A(x)=750x−5x^2/2
A'(x) = 750-10x/2
Setting A'(x) = 0
750-10x/2 = 0
750-10x = 2×0
750-10x = 0
750= 10x
x = 750/10
x = 75
Now that we have x = 75
We can now substitute into equation (*)
A(x) = 750×75-5×75^2/2
= (56250-28125)/2
= 28126/2
= 14062.5
Hence the rectangular region of maximum area is
14062.5ft^2
Answer:
1cm to 200cm
Step-by-step explanation:
l of giraffe = 6m = 600cm
l of giraffe drawing = 3cm
scale = drawing : real = 3 : 600 = 1 : 200
Therefore the scale is 1cm to 200cm
Answer:
5p+4>14 (A)
Step-by-step explanation:
Open dot means that the value is not included.
Answer:
x=16
Step-by-step explanation:
- Just divide it as a decimal (40/2.5)
