Find the vertex I’d this parabola y=-2x^2-4x+4
1 answer:
Answer:
(-1, 6)
Step-by-step explanation:
A graphing calculator shows the vertex to be (x, y) = (-1, 6).
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You can also find it by putting the equation into vertex form.
y = -2(x^2 +2x) +4
y = -2(x^2 +2x +1) +4 +2(1) . . . . . add 1 inside parens; the opposite outside
y = -2(x +1)^2 +6
Compare to ...
y = a(x -h)^2 +k
and you see a=-2, h=-1, k=6
The vertex is (h, k) = (-1, 6).
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Answer:
The inverse function of f(x) is ... f⁻¹(x) = log (x/9.16)/log (1.0054)
Step-by-step explanation:
Starting equation... f(x) = 9.16(1.0054)ˣ
Visually rewritten... y = 9.16(1.0054)ˣ
Flipping x and y... x = 9.16(1.0054)ʸ
Isolating (1.0054)ʸ... x/9.16 = (1.0054)ʸ
Taking the log of both sides... log (x/9.16) = y log (1.0054)
Isolating y... log (x/9.16)/log (1.0054) = y
Solution... y = log (x/9.16)/log (1.0054)
