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Lemur [1.5K]
3 years ago
8

A company’s weighted average cost of capital is 10.8% per year and the market intrinsic value of its debt is $33.1 million. The

company’s free cash flow next year is expected to be $4.7 million and the free cash flow is expected to grow forever at a rate of 3.7% per year. If the company has three million shares of common stock outstanding, what is the intrinsic value per share? Question 6 options: A) $13.72 B) $9.48 C) $11.03 D) $12.24 E) $15.12
Business
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

C. $11.03

Explanation:

We need to first compute the firm's value which is shown below.

Firm's value = Free cash flow ÷ (Weighted average cost of capital - Growth rate)

Firm's value = $4.7 million ÷ ( 10.8% - 3.7%)

= $4.7 million ÷ 7.1%

= $66,197,183

Stock price = (Firm value - Debt) ÷ Number of shares

= ($66,197,183 - $33,100,000) ÷ 3,000,000

= $33,097,183 ÷ 3,000,000

= $11.03

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Answer:

The correct answer is letter "B": The decisions you make are constantly changing with imperfect information available.

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Besides, the information entered in the system must be perfect to obtain an accurate outcome. However, decision-making is based on data that can be precise like the information portrayed in the financial books of the firm but<em> if there is a mistake committed, even if minimal, the programmed decision could fail.</em>

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You are interested in valuing a 2-year semi-annual corporate coupon bond using spot rates but there are no liquid strips availab
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Answer:

Following are the solution to this question:

Explanation:

Assume that r_1  will be a 12-month for the spot rate:

\to 1.25 \% \times \frac{100}{2} \times 0.99 + \frac{(1.25\% \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{100} \times \frac{100}{2} \times 0.99 + \frac{(\frac{1.25}{100} \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{2} \times 0.99 + \frac{(\frac{1.25}{2} +100)}{(1+\frac{r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 0.625 +100)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 100.625)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\

\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\\to 0.61875 -98 = \frac{402.5}{(2+r_1)^2}\\\\\to -97.38125= \frac{402.5}{(2+r_1)^2}\\\\\to (2+r_1)^2= \frac{402.5}{ -97.38125}\\\\\to (2+r_1)^2= -4.13\\\\ \to r_1=3.304\%

Assume that r_2  will be a 18-month for the spot rate:

\to 1.5\% \times \frac{100}{2} \times 0.99+1.5\%  \times \frac{100}{2} \times \frac{1}{(1+ \frac{3.300\%}{2})^2}+\frac{(1.5\%  \times  \frac{100}{2}+100)}{(1+\frac{r_2}{2})^3}=97\\\\\to \frac{1.5}{100} \times \frac{100}{2} \times 0.99+\frac{1.5}{100}  \times \frac{100}{2} \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{100}  \times  \frac{100}{2}+100)}{(1+\frac{r_2}{2})^3}=97\\\\

\to \frac{1.5}{2}  \times 0.99+\frac{1.5}{2}\times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{2} +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 0.7425+0.75 \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(0.75  +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1+0.0165)^2}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1.033)}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\

\to 1.4925 \times 0.96+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328-97= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to -95.5672= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to (1+\frac{r_2}{2})^3= -1.054\\\\\to r_2=3.577\%

Assume that r_3  will be a 18-month for the spot rate:

\to 1.25\% \times \frac{100}{2} \times 0.99+1.25\% \times \frac{100}{2} \times \frac{1}{(1+\frac{3.300\%}{2})^2}+1.25\%\times\frac{100}{2} \times \frac{1}{(1+\frac{3.577\%}{2})^3}+(1.25\% \times \frac{\frac{100}{2}+100}{(1+\frac{r_3}{2})^4})=96\\\\

to solve this we get r_3=3.335\%

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