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Kay [80]
3 years ago
14

SOMEONE PLEASE HELPS ME HOW TO FIND THIS PLEASEEE #5

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0
The angle for a straight line is 180 degrees. So, to find x, you must subtract the angle given from the angle from the straight line to get 180-151=29 degrees.
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The measures of the legs of a right triangle are 15 m and 20 m. Use the triangle measures and substitute the lengths for a and b
DochEvi [55]

Answer:

25

Step-by-step explanation:

We can use the Pythagorean theorem to determine the length of the hypotenuse

a^2 + b^2 = c^2

15^2 + 20 ^2 = c^2

225 + 400 = c^2

625 = c^2

Take the square root of each side

sqrt(625) = sqrt(c^2)

25 = c

5 0
3 years ago
Which two numbers on the number line have an absolute value of 1.75? Select the location of both numbers on the number line
hram777 [196]

Solution

             To    find   Which two numbers on the number line have  sn  

            absolute value of 1.75  .

            Absolute   value   means    " how  far   a  number    is   from  

            zero "  .

           "1.75"    is    1.75   away   from   zero  .

           and  " -1.75"   is  also   1.75    away   from  zero  .

          i.e

               |  0  - 1.75 |   =   1.75

              |  1.75 - 0 |  =  1.75  

           So ,  the  absolute   value  of   "1.75"    is  1.75  

          similarly  , absolute  value  of  "1.75"   is   1.75  .

          Hence  , the  two  numbers   are   -1.75  and  1.75  .

                 

           

8 0
3 years ago
Read 2 more answers
I have some questions that need to be answered fast.<br><br> 1. 42/j = 35/55
Novay_Z [31]

\frac{42}{j}  =  \frac{35}{55}

to solve for j first you need to cross multiply;

j × 35 = 42 × 55

35j = 2,310

j = 2,310 ÷ 35 (did the inverse operation)

j = 66

Hope that helps :D

6 0
3 years ago
Da<br> A<br> Solve the equation 2x^2+3=0
Anika [276]

Answer:

x = ±i(√6 / 2)

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

  • Solving quadratics

<u>Algebra II</u>

Imaginary root i

  • √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2x² + 3 = 0

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Subtraction Property of Equality] Subtract 3 on both sides:                        2x² = -3
  2. [Division Property of Equality] Divide 2 on both sides:                                  x² = -3/2
  3. [Equality Property] Square root both sides:                                                    x = ±√(-3/2)
  4. Simplify:                                                                                                             x = ±i(√6 / 2)
4 0
3 years ago
How do I show my work for this ?
Zarrin [17]
First, you multiply all terms by 2.8 to get rid of the denominator:
m-13.72 = -19.908
then, you isolate the m on one side of the equation and all other terms on the other side:
m = -19.908+13.72
m = -6.188
3 0
3 years ago
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