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vfiekz [6]
3 years ago
14

Peter is making an "X marks the spot" flag for a treasure hunt. The flag is made of a square white flag with sides of 12 inches.

He will make the "X" by stretching red ribbon diagonally from corner to corner. How many inches of ribbon will Peter need to make the "X"? Round your answer to the nearest inch.
Mathematics
1 answer:
Nataly_w [17]3 years ago
7 0
To answer this question you can use the Pythagorean Theorem Which states that a squared plus b squared equals c squared. C is the hypotenuse of a triangle (one of the diagonals forming the X). The hypotenuse is the side directly across from the right angle. A and b are both 12, so 12 squared plus 12 squared is 288. To solve for c, find the square root of 288, which is approximately 17 inches. Double this (one for each line in the X and you need approximately 34 inches of ribbon. Always label your answers!
You might be interested in
A shoe dealer purchased net Birr 8,000 worth of shoes from a shoe company.
Alex787 [66]

Answer:

Step-by-step explanation:

A) The dealer bought Birr 8000 at 7% tax.

Total amount to be paid = cost price (1 + r%)

r = 7% = 0.07

Total amount to be paid = 8000 \times 1.07 =\texttt {Birr}  \ \  {8,560}

B) To find the VAT, it is the difference between the tax paid when the good was bought and the tax put on it after it was sold.

Tax paid when the shoes were bought = 7% of cost price

= 7 \%  \times  8,000 = \texttt {Birr} \ 560

Tax paid when the shoes were sold = 9% of selling price

= 9 \% \times 12,000 = \texttt {Birr} \ 1,080

VAT = tax recovered on sale - Tax paid on purchase

\texttt {VAT} = 1080 - 560 = \texttt {Birr}\ 520

8 0
3 years ago
Can anybody help plzz?? 65 points
Yakvenalex [24]

Answer:

\frac{dy}{dx} =\frac{-8}{x^2} +2

\frac{d^2y}{dx^2} =\frac{16}{x^3}

Stationary Points: See below.

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Calculus</u>

Derivative Notation dy/dx

Derivative of a Constant equals 0.

Stationary Points are where the derivative is equal to 0.

  • 1st Derivative Test - Tells us if the function f(x) has relative max or mins. Critical Numbers occur when f'(x) = 0 or f'(x) = undef
  • 2nd Derivative Test - Tells us the function f(x)'s concavity behavior. Possible Points of Inflection/Points of Inflection occur when f"(x) = 0 or f"(x) = undef

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Quotient Rule: \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

f(x)=\frac{8}{x} +2x

<u>Step 2: Find 1st Derivative (dy/dx)</u>

  1. Quotient Rule [Basic Power]:                    f'(x)=\frac{0(x)-1(8)}{x^2} +2x
  2. Simplify:                                                      f'(x)=\frac{-8}{x^2} +2x
  3. Basic Power Rule:                                     f'(x)=\frac{-8}{x^2} +1 \cdot 2x^{1-1}
  4. Simplify:                                                     f'(x)=\frac{-8}{x^2} +2

<u>Step 3: 1st Derivative Test</u>

  1. Set 1st Derivative equal to 0:                    0=\frac{-8}{x^2} +2
  2. Subtract 2 on both sides:                         -2=\frac{-8}{x^2}
  3. Multiply x² on both sides:                         -2x^2=-8
  4. Divide -2 on both sides:                           x^2=4
  5. Square root both sides:                            x= \pm 2

Our Critical Points (stationary points for rel max/min) are -2 and 2.

<u>Step 4: Find 2nd Derivative (d²y/dx²)</u>

  1. Define:                                                      f'(x)=\frac{-8}{x^2} +2
  2. Quotient Rule [Basic Power]:                  f''(x)=\frac{0(x^2)-2x(-8)}{(x^2)^2} +2
  3. Simplify:                                                    f''(x)=\frac{16}{x^3} +2
  4. Basic Power Rule:                                    f''(x)=\frac{16}{x^3}

<u>Step 5: 2nd Derivative Test</u>

  1. Set 2nd Derivative equal to 0:                    0=\frac{16}{x^3}
  2. Solve for <em>x</em>:                                                    x = 0

Our Possible Point of Inflection (stationary points for concavity) is 0.

<u>Step 6: Find coordinates</u>

<em>Plug in the C.N and P.P.I into f(x) to find coordinate points.</em>

x = -2

  1. Substitute:                    f(-2)=\frac{8}{-2} +2(-2)
  2. Divide/Multiply:            f(-2)=-4-4
  3. Subtract:                       f(-2)=-8

x = 2

  1. Substitute:                    f(2)=\frac{8}{2} +2(2)
  2. Divide/Multiply:            f(2)=4 +4
  3. Add:                              f(2)=8

x = 0

  1. Substitute:                    f(0)=\frac{8}{0} +2(0)
  2. Evaluate:                      f(0)=\text{unde} \text{fined}

<u>Step 7: Identify Behavior</u>

<em>See Attachment.</em>

Point (-2, -8) is a relative max because f'(x) changes signs from + to -.

Point (2, 8) is a relative min because f'(x) changes signs from - to +.

When x = 0, there is a concavity change because f"(x) changes signs from - to +.

3 0
3 years ago
PLZ HELP!<br>dont just answer something random for points:)tysm​
sergiy2304 [10]

Answer:

4(x^{2} -4)^{2} -76

Step-by-step explanation:

Take out 4:

4(x^2-8x)-12

=4(x^2-8x+16-16)-12

=4(x^2-8x+16)-64-12

=4(x^2-4)^2 - 76

=4(x^{2} -4)^{2} -76

6 0
3 years ago
On a coordinate plane, a shape is plotted with vertices of (3, 1), (0, 4), (3, 7), and (6, 4). what is the area of the shape if
QveST [7]
Let
<span>A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)

step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm

step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm

step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm

step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm

step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD

step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and 
AB and AD are perpendicular 
BC and CD are perpendicular

therefore
the shape is a square wit length side √18 cm

area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²

the answer is
18 cm²

see the attached figure


6 0
3 years ago
What is the slope of the line that passes through the points (3 -1) and (-2 -5)
natima [27]
The slope is

(difference in y-values) / (difference in x-values)

= (-4) / (-5)

= 0.8
4 0
3 years ago
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