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3 years ago

A rectangular piece measures 3 1/2 yards long by 2 1/4 yards wide. What is the area of this piece of fabric?

Mathematics

2 answers:

Artemon [7]3 years ago

7 0

50 is the final answer! :)

Oksi-84 [34.3K]3 years ago

4 0

50 because i know the answer to it

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3. i) Determine the volume of the cylinder above to the nearest cubic centimetre. (3 points)

klemol [59]

Answer:

1480cm³

Step-by-step explanation:

The Equation for the Volume of a Cylinder is V=Bh, where B is the area of the circle (A= πr²).

We are given all of the things we need, we just have to plug them into the equation.

First let's find B using the radius(r) which is given to be 6.4cm, so B=πr²

B=π(6.4cm)²

Plug that into a calculator to get 128.6796351cm²

Now we can plug that into the original equation, V=Bh.

V=(128.6796351cm²)h

h is also given to be 11.5cm, so lets plug that in.

V=(128.6796351cm²)(11.5cm)

You will get V=1479.815804cm³, but since we are rounding to the nearest cubic centimeter, we would round up to 1480cm³.

3 0

3 years ago

What of the following functions is graphed below

leva [86]

The correct answer is C

5 0

3 years ago

Mai has 40 tens and how many hundreds

Ipatiy [6.2K]

40 x 10 = 400
400 / 100 = 4
Mai has 4 hundreds.

5 0

3 years ago

Read 2 more answers

Help me pleaseeee :)

PilotLPTM [1.2K]

Answer:

first from the top

Step-by-step explanation:

8 0

3 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

3 years ago