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3 years ago

Classify the following triangle. Check all that apply

Mathematics

2 answers:

pogonyaev3 years ago

8 0

Its B and D thats all i know about it you can trust this answer.

kramer3 years ago

7 0

D and E. If I remember right that should be the answer.

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5. Solve for x using any method you'd like. Round to the hundredth. Show all your work. (2 points each) d. 20x^3 = 7x^5

Sindrei [870]

Solving this equation for x, we have:

$\begin{gathered} 20x^3=7x^5 \\ 7x^5-20x^3=0 \\ x^3(7x^2-20)=0 \\ \begin{cases}x^3=0\to x=0 \\ 7x^2=20\to x=\pm\sqrt[]{\frac{20}{7}}\end{cases} \end{gathered}$

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1 year ago

What is 6,4 rounded to the nearest whole number

Aleks04 [339]

6.4 rounded to the nearest whole number will be 6.

if the decimal was 5 or larger, it would’ve been 7.

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3 years ago

Is the relation represented in this table a function?

Inessa05 [86]

Answer:

i think so?

Step-by-step explanation:

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3 years ago

Read 2 more answers

Carman spent 42$ on 6 hats how much did each hat cost. Its for my sisters elementary school class and i dont even know the awnse

Travka [436]

Answer: 7

Step-by-step explanation:

Step 1: Since it is asking how much each hat costed. We would divide.

42$ divide 6 = 7$ per hat

8 0

3 years ago

Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!

kupik [55]

Answer:

The equation of required line is: $\mathbf{5x-8y+34=0}$

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to $5x-8y+12=0$ and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line $5x-8y+12=0$ to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: $y=mx+b$ where m is slope.

$5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}$

So, the slope m = 5/8

The slope of required line is $m=\frac{5}{8}$

Now finding y-intercept using slope $m=\frac{5}{8}$ and point(-2,3)

$y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}$

So, the equation of required line having slope $m=\frac{5}{8}$ and y-intercept $b=\frac{17}{4}$

$y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8} \\8y=5x+34\\5x-8y+34=0$

So, The equation of required line is: $\mathbf{5x-8y+34=0}$

3 0

3 years ago