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lions [1.4K]
3 years ago
5

A grocery store so the six pack of bottled water for $3.79 a 12 pack for $6.89 which package cost The least per bottle explain y

our reasoning
Mathematics
1 answer:
il63 [147K]3 years ago
4 0
Easiest way to find out the answer to this is to find out the price of every water bottle. To do that you have to divide the whole value by the amount of water bottles. (3.79/6 & 6.89/12) The first one should equal something around .63 each and the second should be around .57. Technically the second pack is cheaper than the other by around .6 cents.
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In the triangles, and . Which statement correctly compares the angles? Angle G is congruent to angle P. Angle G is smaller than
GalinKa [24]

Answer: angle g

Step-by-step explanation:   Angle G is smaller than angle P. Angle G is larger than angle P. Angle G is congruent to angle N. 2 Consider the triangle.

3 0
3 years ago
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Compare 9.36 and 9.359
Sati [7]

Try this option (this is not the only way!):

1. the rule: if 'number_1' - 'number_2' > 0, then number_1>number_2. If 'number_1'-'number_2'<0, then number_2>number_1.

2. according to the rule above: 9.36-9.359=0.001. 0.001>0, it means, 9.36>9.359.

6 0
3 years ago
39 is 5% of what number?
Inessa05 [86]

Answer:

780

Step-by-step explanation:

Explanation:

To get from  

5% to 100% you multiply by 20, so multiply the number in this case 39 by 20 percent.

6 0
3 years ago
I need help.. i really want to go sleep.. thank you so much...
Effectus [21]

Answer:

1) True 2) False

Step-by-step explanation:

1) Given  \sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}

To verify that the above equality is true or false:

Now find \sum\limits_{k=0}^8\frac{1}{k+3}

Expanding the summation we get

\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{0+3}+\frac{1}{1+3}+\frac{1}{2+3}+\frac{1}{3+3}+\frac{1}{4+3}+\frac{1}{5+3}+\frac{1}{6+3}+\frac{1}{7+3}+\frac{1}{8+3} \sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}

Now find \sum\limits_{i=3}^{11}\frac{1}{i}

Expanding the summation we get

\sum\limits_{i=3}^{11}\frac{1}{i}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}

 Comparing the two series  we get,

\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i} so the given equality is true.

2) Given \sum\limits_{k=0}^4\frac{3k+3}{k+6}=\sum\limits_{i=1}^3\frac{3i}{i+5}

Verify the above equality is true or false

Now find \sum\limits_{k=0}^4\frac{3k+3}{k+6}

Expanding the summation we get

\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3(0)+3}{0+6}+\frac{3(1)+3}{1+6}+\frac{3(2)+3}{2+6}+\frac{3(3)+4}{3+6}+\frac{3(4)+3}{4+6}

\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}+\frac{12}{8}+\frac{15}{10}

now find \sum\limits_{i=1}^3\frac{3i}{i+5}

Expanding the summation we get

\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3(0)}{0+5}+\frac{3(1)}{1+5}+\frac{3(2)}{2+5}+\frac{3(3)}{3+5}

\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}

Comparing the series we get that the given equality is false.

ie, \sum\limits_{k=0}^4\frac{3k+3}{k+6}\neq\sum\limits_{i=1}^3\frac{3i}{i+5}

6 0
3 years ago
A 90-day simple interest loan in the amount of $2350 will be paid in full in the amount of $2500 . Find the rate of the loan.
ivolga24 [154]

Answer:

The rate of simple interest is 25.89 %  

Step-by-step explanation:

Given as :

The principal = $2350

The Amount = $2500

The time period = 90 days = \frac{90}{365} year = 0.2465 year

Let The rate of interest = R %

So, Interest = Amount - Principal

Or, Interest = $2500 - $2350 = $150

<u>From Simple Interest method </u>

Simple Interest = \frac{Principal\times rate\times Time}{100}

Or, $150 =  \frac{$2350\times rate\times 0.2465 }{100}

or, $150 × 100 = $579.275  × Rate

So, Rate = \frac{15000}{579.275}

∴    Rate = 25.89 %

Hence The rate of simple interest is 25.89 %    Answer

6 0
3 years ago
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