Question

Is this problem correct??

Answer 1

Hey there !

Yeah , the problem is absolutely correct , and here is the solution -

$y = {2}^{3x - 1}$

To find inverse , first switch x and y ,
$x = {2}^{3y - 1}$

Taking log both sides ,
$log(x) = (3y - 1) log(2) \\ \\ \frac{ log(x) }{ log(2) } = 3y - 1 \\ \\ \: \: y = \frac{ log_{2}(x) }{3} \: \: \: \: \: \: ans.$

Hope it helps you :)