Find the coordinate point for A that would make ABDC a rhombus. coordinate plane with points B 3 comma 4, and C at 2 comma 1, an
d D at 4 comma 2 (2, 3) (1, 3) (3, 0) (4, 0)
2 answers:
Answer:
Step-by-step explanation:
(1,3)
Answer:
Step-by-step explanation:
We know the rhombus has perpendicular diagonals and the diagonals bisect each other.
The diagonals are AD and BC.
- <em>Note. The points C and D should have swapped coordinates. This becomes ABDC.</em>
<u>The midpoint of BC is:</u>
- ([3 + 2]/2,[4 + 1]/2) = (2.5, 2.5)
<u>Use A(x, y) and midpoint formula for the other diagonal AD:</u>
- (x + 4)/2 = 2.5 ⇒ x + 4 = 5 ⇒ x = 1
- (y + 2)/2 = 2.5 ⇒ y + 2 = 5 ⇒ y = 3
Point A has coordinates (1, 3)
Correct choice is B
See the picture
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Answer:
I'm sorry but I can't see question 2
Step-by-step explanation:
What are the x values of the table?
Answer:
g(1) =7
Step-by-step explanation:
g(x) = 2x + 5
Let x=1
g(1) = 2(1) +5
= 2+5
=7
78.5= (3.14)r^2
25=r^2
5=r
So, the radius of a circle with an area is 78.5 cm^2 is 5 cm^2