Try redo this question on your own incase I may have mistake.. tq
Find the coordinate point for A that would make ABDC a rhombus. coordinate plane with points B 3 comma 4, and C at 2 comma 1, an
2 answers:
Answer:
- B. (1, 3)
Step-by-step explanation:
We know the rhombus has perpendicular diagonals and the diagonals bisect each other.
The diagonals are AD and BC.
- <em>Note. The points C and D should have swapped coordinates. This becomes ABDC.</em>
<u>The midpoint of BC is:</u>
- ([3 + 2]/2,[4 + 1]/2) = (2.5, 2.5)
<u>Use A(x, y) and midpoint formula for the other diagonal AD:</u>
- (x + 4)/2 = 2.5 ⇒ x + 4 = 5 ⇒ x = 1
- (y + 2)/2 = 2.5 ⇒ y + 2 = 5 ⇒ y = 3
Point A has coordinates (1, 3)
Correct choice is B
See the picture
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Answer:
x=4
Step-by-step explanation:
We are given that the triangles are congruent.
Specifically, the order of the letters gives that the angles ∠DAB and ∠CBA are corresponding parts of the two congruent triangles. Since corresponding parts of congruent triangles are themselves congruent, ∠DAB ≅ ∠CBA. Thus, m∠DAB = m∠CBA.
Given the expressions for the two angles, we can substitute into the equation, and solve for the requested variable.