You want to find the number of visits IN BETWEEN 12:30 PM and 6:45 PM
there some visits already recorded before 12:30. These visits are visits that you want to exclude but are included in the TOTAL visits
Before 12:30 the website has 1200 visits and at 6:45 the website has 14000.
You can do 14000-1200 to find the number of visits in the time frame between 12:30 and 6:45
ANSWER 12800 visits
Answer:
68
Step-by-step explanation:
you have to add to 180 and 68+112=180
Answer:
-7
Step-by-step explanation:
you divide both sides by -2 and 14/-2 is equal to -7
Answer:
i dont know ask brainly.
Step-by-step explanation:
That "ad^3" bothers me; I'm not sure what you mean here.
I'm going to assume that you have (1/4*a*d^3)^2.
If that's the case, then you have (1/4)^2 * a^2 * d^6 = (1/16)*a^2*d^6.
If this is not what you were hoping for, double check to ensure that you have copied down this problem exactly as it was presented.
