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deff fn [24]
3 years ago
15

(1) a sample of 36 ball have been randomly pull out of jar. it contained 16 red balls. what is the probability of that happening

? do you still believe that jar contains 25% red balls?
Mathematics
1 answer:
Lynna [10]3 years ago
4 0
There is a .41025...% chance of that happening. moving on the jar is not 25% filled with red balls because 25% of 36 is only 9 and he pulled out 16 red balls hence forth that is impossible if the jar is only 25% red balls 

hope this helped!!!
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Jill has 200 movies downloaded on her phone. Of these movies 24 are comedies. What percent of Jills movies are comedies?
katen-ka-za [31]

Answer:

12%

12% of Jill's movies are comedies.

Step-by-step explanation:

24/200 x 100/1= 12%

7 0
3 years ago
(PLEASE HELP ASAP)
UNO [17]

9514 1404 393

Answer:

  A. 3×3

  B. [0, 1, 5]

  C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.

Step-by-step explanation:

A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.

This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...

  A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)

Matrix A is 3×3.

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B. The second row of A represents the second equation:

  0x_1+1x_2+5x_3=-1

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.

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C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)

6 0
2 years ago
What are the first three terms of the sequence...plz help pt.1​
svetlana [45]

a_{n} \:  =  \: 2(a_{n - 1})^{2} \\ a_{1} = 4 \: (given) \\ a_{2} = \: 2(a_{2 - 1})^{2}  \\  = 2(a_{ 1})^{2}   \\  = 2 \times  {4}^{2}  \\  = 32 \\  \\ a_{3} = \: 2(a_{3 - 1})^{2}  \\  = 2(a_{ 2})^{2}   \\  = 2 \times  {32}^{2}  \\  = 2 \times 1024 \\  = 2048

so first 3 terms are

4, 32, 2048

8 0
3 years ago
Read 2 more answers
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
3 years ago
122 - 4(6) +1<br> 112p hellllllp
Rasek [7]

Answer:

99

Step-by-step explanation:

U will do the one outside first

122+1-4(6)

=123-24

= 99

7 0
2 years ago
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