The area of the room is 147.5 square feet so Michelle's reasoning was incorrect.
Step-by-step explanation:
Step 1:
To calculate the area of the given room, we divide the unknown shape into known shapes.
The room's shape is made of 2 rectangles.
The area of a rectangle is the product of its length and its width.
One rectangle has a length of 10 feet and a width of 12 1/2 feet.
The other rectangle has a length of 15 - 10 = 5 feet and a width of 4 1/2 feet.
Step 2:
The area of the first rectangle = (10)(12 1/2) = (10)(12.5) = 125 square feet.
The area of the second rectangle (10)(4 1/2) = (5)(4.5) = 22.5 square feet.
The total area of the room = 125 + 22.5 = 147.5 square feet.
1. Know what you're looking for:
The range is the difference between the lowest and highest values.
Your weight is 145.2 and can vary from the actual weight by maximum 0.3 lbs less or maximum 0.3 lbs more.
2. Calculate your lowest and highest values :
Lowest : 145.2 - 0.3 = 144.9 lbs
Highest : 145.2 + 0.3 = 145.5 lbs
3. Calculate the range of actual weights of the object :
145.5 - 144.9 = 0.6 lbs
--> The answer is: <u>The range of actual weights of the object is 0.6 lbs.</u>
There you go! I really hope this helped, if there's anything just let me know! :)
The answer is one and five elevenths, or: 1 5/11
this is because 140/2.5 is 56 and 300/5.5 is 54 6/11.
56 - 54 6/11= 1 5/11
It’s the point where the parabola crosses its axis of symmetry