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olga55 [171]
3 years ago
12

Someone please solve this from 1 to 10

Mathematics
1 answer:
gladu [14]3 years ago
8 0
4x - 6 = x + 9
4x - x = 9 + 6
3x = 15
x = 15/3
x = 5
==============
4 - 7x = 1 - 6x
4 - 1 = -6x + 7x
3 = x
==============
-4x - 3 = -6x + 9
-4x + 6x = 9 + 3
2x = 12
x = 12/2
x = 6
==============
41 - 2x = 2 + x
41 - 2 = x + 2x
39 = 3x
39/3 = x
13 = x
===============
6(2 + y) = 3(3-y)
12 + 6y = 9 - 3y
6y + 3y = 9 - 12
9y = - 3
y = -3/9
y = -1/3
==============
4x = 2(x - 5) - 2
4x = 2x - 10 - 2
4x - 2x = -10 - 2
2x = -12
x = -12/2
x = -6
===============
6x - 9x - 4 = -2x - 2
-3x - 4 = -2x - 2
-4 + 2 = -2x + 3x
-2 = x
==============
-2(2x + 3) = -4(x + 1) - 2
-4x - 6 = -4x - 4 - 2
-4x - 6 = -4x - 6
infinite solutions
================
3 + 6x = 9 - 6x
3 - 9 = -6x - 6x
-6 = -12x
-6/-12 = x
1/2 = x
==============
-9x + 6 = -x + 4
6 - 4 = -x + 9x
2 = 8x
2/8 = x
1/4 = x

I hope I read these correctly....not that easy...u got weird looking x's and ur 4's can almost pass for 6's



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4 years ago
Suppose you just received a shipment of twelve televisions. Three of them are defective. Assuming that two televisions are rando
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<span>The probability that both televisons work is 18/33.
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</span>
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The probability of 1 not working among the two can be solved through"
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</span>

Thank you for posting your question. I hope you found you were after. Please feel free to ask me another.


4 0
4 years ago
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