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USPshnik [31]
3 years ago
8

Helppppppppppppppppp

Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

Answer:37.7825

Step-by-step explanation: all you really need to do is find the percentage of 595 of 6.35 which is 37.7825

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A researcher wishes to​ estimate, with 9090​% ​confidence, the proportion of adults who have​ high-speed Internet access. Her es
Sunny_sXe [5.5K]

Answer:  a) Required minimum sample size= 219

b) Required minimum sample size= 271

Step-by-step explanation:

As per given , we have

Margin of error : E= 5% =0.05

Critical z-value for 90% confidence interval : z_{\alpha/2}=1.645

a) Prior estimate of true proportion: p=28%=0.28

Formula to find the sample size :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.28(1-0.28)(\dfrac{1.645}{0.05})^2\\\\=218.213856\approx219

Required minimum sample size= 219

b) If no estimate of true proportion is given , then we assume p= 0.5

Formula to find the sample size :-

n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.645}{0.05})^2\\\\=270.6025\approx271

Required minimum sample size= 271

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2 years ago
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