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3 years ago

25 points! Please help me!

Mathematics

2 answers:

fgiga [73]3 years ago

8 0

When x = 5. Plug in 5 for x

f(5) = -5(5) - 4

Remember to follow PEMDAS. First, multiply -5 with 5

-5 x 5 = -25

Next, subtract 4

f(5) = -25 - 4

f(5) = -29

B. f(5) = −29 is your answer

hope this helps

Slav-nsk [51]3 years ago

5 0

Replace X with 5 in the equation and solve:

f(x) = -5x-4, X = 5

f(5) = -5(5) - 4

f(5) = -25 - 4

f(5) = -29

The answer is B.

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3 years ago

In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.

Hitman42 [59]

$\longmapsto$ The value of "x" is 5.

$\large\underline{\sf{Solution-}}$

Given that,

A trapezium ABCD in which AB || CD such that

AO = x - 1

CO = BO = x + 1

OD = x + 4

Now,

$\rm In \: \triangle \: AOB \: and \: \triangle \: COD$

$\rm \: \angle \: AOB \: and \: \angle \: COD \: \: \{vertically \: opposite \: angles \}$

$\rm \: \angle \:ABO \: and \: \angle \: CDO \: \: \{alternate \: interior \: angles \}$

$\bf \: \triangle \: AOB \: \sim \: \triangle \: COD \: \: \: \{AA \: similarity \}$

$\bf\longmapsto\:\dfrac{AO}{CO} = \dfrac{BO}{DO}$

$\rm \longmapsto\:\dfrac{x - 1}{x + 1} = \dfrac{x + 1}{x + 4}$

$\rm \longmapsto\:(x - 1)(x + 4) = {(x + 1)}^{2}$

$\rm \longmapsto\: {x}^{2} - x + 4x - 4 = {x}^{2} + 1 + 2x$

$\rm \longmapsto\: 3x - 4 = 1 + 2x$

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$\bf\longmapsto \:x = 5$

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3 years ago

What is the range of the function g(t)=t2−5 g ( t ) = t 2 − 5 when the domain is defined as the set of integers, t, t , such tha

Andrej [43]

g(t) = t² - 5

g(-4) = (-4)² - 5 = 16 - 5 = 11

<em>at this point, you can tell that B is the answer, but I will continue on so you know how to solve similar problems.</em>

g(-3) = (-3)² - 5 = 9 - 5 = 4

g(-2) = (-2)² - 5 = 4 - 5 = -1

g(-1) = (-1)² - 5 = 1 - 5 = -4

g(0) = (0)² - 5 = 0 - 5 = -5

g(1) = (1)² - 5 = 1 - 5 = -4

g(2) = (2)² - 5 = 4 - 5 = -1

Answer: B

5 0

3 years ago