X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
Square <span>polygon is always regular, other have some scenarios which makes them regular but they are not always regular.</span>
Answer:
(2, 0)
Step-by-step explanation:
The x intercept is when y is equal to 0.
Therefore,
8x-1/3*0=16
8x=16
x=2
The answer is (2,0)
3 cm on the map represents 31.5 km in reality.
3cm : 31.5 km
1cm : 31.5/3 km
1cm : 10.5km
So the scale on the map is 1cm represents 10.5 km.
Answer:
1) The terminal side lies in quadrant 2
2) cosФ = -15/17
3) tanФ = -8/15
Step-by-step explanation:
1) First, we should realize that since sinФ = 8/17, it is positive. Thus, Ф must be in quadrants 1 or 2. And since cosФ is negative, Ф must be in quadrant 2 because cos, sin, and tan are all positive in quadrant 1
2) Next, we must realize that the sides given are a 8-15-17 right triangle. And in this case, since sinФ = 8/17, cosФ should be 15/17. But since cosФ is negative, cosФ = -15/17
3) Lastly, tanФ is opposite/adjacent. Since opposite of Ф is 8 and adjacent of Ф is 15, then tanФ should be 8/15, but since Ф is in quadrant 2, then tanФ is -8/15
