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Deffense [45]
3 years ago
15

The graph below shows three functions: Graph of function f of x equals 0.5 to the power x. Graph of function g of x is a line se

gment with holes at endpoints connecting negative 1.8, negative 3 and 1, 3.8. Graph of p of x is a line segment connecting negative 1.7, 2.3 and 1, negative 4.2. Which function has all real numbers as its domain?

Mathematics
2 answers:
Phantasy [73]3 years ago
8 0

Answer:   f(x)= 0.5^x has all real value as its domain.

Explanation: since, we have three functions f(x)=0.5^x,

while g(x) and p(x) are line segments.

Now, g(x) is a function by a line segment which passes through two points (-1.8,-3) and ( 1,3.8).

Thus it is clear that its domain will be the ends points. so domain of the function g(x) will be [-1.8, 3.8] which is the subset of real numbers set (R).

Similarly, domain of function p(x) will be [1.7, 1], which is also the subset of R.

But, when we talk about f(x) it contains all the possible value of x. Thus we can say that f(x)= 0.5^x has R as its domain.

MArishka [77]3 years ago
7 0
<span>p(x) contains all real numbers as its domain because both of the other functions are only line segments and cover a finite interval of x.</span>
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Answer:

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Step-by-step explanation: 12,000 x 4 = 48,000

48,000 + 198,000 = 246,000


3 0
3 years ago
Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.3 and P(B) = 0.7. If
Thepotemich [5.8K]

Answer:

See below

Step-by-step explanation:

What is P(A B)?

If A and B are mutually exclusive, then  

P(AB) = P(A∩B) = P(∅) = 0

What is P(A | B)?

By definition  

<em>P(A | B) =  P(A∩B)/P(B). </em>

Since  

P(A∩B) = 0, then P(A | B) = 0

Is P(A | B) equal to P(A)?

No, because P(A | B) = 0 and P(A) = 0.3

Are events A and B dependent or independent?

A and B would be independent if

P(A | B) = P(A) and P(B | A) = P(B)

But both P(A |B) and P(B | A) equals 0 and P(A) = 0.3, P(B) = 0.7

Hence, <em>A and B are dependent. </em>

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?

No, it is not.

As we already saw, A and B are mutually exclusive but they are not independent.

What general conclusion would you make about mutually exclusive and independent events given the results of this problem?

If A and B are not empty events which are mutually exclusive, they can never be independent.

6 0
3 years ago
What is the y-intercept of y = 5?
Vikentia [17]

Answer:

The answer is .

whenever y equals 5 this usually means that 5 is the answer because on the Y intercept it usually is just five but if you had x equals 7 the x intercept would be 7 .

3 0
3 years ago
Determine, using the intermediate value theorem, if the function F(x)=x^3+2x-1 has a zero on the interval [0,1]. Justify your an
SSSSS [86.1K]

Plug x = 0 into the function

f(x) = x^3 + 2x - 1

f(0) = 0^3 + 2(0) - 1

f(0) = -1

Note how the result is negative. The actual number itself doesn't matter. All we care about is the sign of the result.

Repeat for x = 1

f(x) = x^3 + 2x - 1

f(1) = 1^3 + 2(1) - 1

f(1) = 2

This result is positive.

---------------------------

We found that f(0) = -1 and f(1) = 2. The first output -1 is negative while the second output 2 is positive. Going from negative to positive means that, at some point, we will hit y = 0. We might have multiple instances of this happening, or just one. We don't know for sure. The only thing we do know is that there is at least one root in this interval.

To actually find this root, you'll need to use a graphing calculator because the root is some complicated decimal value. Using a graphing calculator, you should find the root to be approximately 0.4533976515

7 0
3 years ago
What is the value of 7(4 + x) when x = 5?
NikAS [45]

Step-by-step explanation:

❉ \underline{ \underline{ \sf{Given}}} :

  • x = 5

❉ \underline{ \underline{ \sf{To \: find}}}  :

  • value of 7 ( 4 + x )

Plug the value of x and simplify :

⟿ \sf{7(4 + 5)}

Add the numbers : 4 and 5

⟿ \sf{7 \times 9}

Multiply 7 by 9

⟿ \boxed{  \sf{63}}

\red{  \boxed{ \boxed{ \tt{⇾Our \: final \: answer : 63}}}}

Hope I helped ! ♪

Have a wonderful day / night ! ツ

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8 0
3 years ago
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