5d+30/2-3d-6/2+2d who ever gets it right will make brainleist answer
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103 adults and 183 children's attended
<em><u>Solution:</u></em>
Let "a" be the number of adults attended
Let "c" be the number of children attended
Cost of 1 adult ticket = $ 12
Cost of 1 children ticket = $ 4
At the movies, we had 286 people buy tickets
Therefore,
number of adults attended + number of children attended = 286
a + c = 286 ---- eqn 1
The total sold was $1968
Therefore,
number of adults attended x Cost of 1 adult ticket + number of children attended x Cost of 1 children ticket = 1968
12a + 4c = 1968 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
a = 286 - c -- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
12(286 - c) + 4c = 1968
3432 -12c + 4c = 1968
-8c = 1968 - 3432
-8c = -1464
8c = 1464
<h3>c = 183</h3><em><u>Substitute c = 183 in eqn 3</u></em>
a = 286 - 183
<h3>a = 103</h3>Thus 103 adults and 183 children's attended