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Irina18 [472]
3 years ago
5

Jillian is participating in a book-reading contest to raise funds for her local library. For every book Jillian reads, her mothe

r pledged to make a donation.
A: The table shows how much Jillian's mother will donate. Find the pattern, and give the amount her mother will donate for 9 and 21 books read.
(Btw it won't let me upload a pic of the table so this is what it said)

BR: 3. 5. 7
MD: $15. $25. $35

(Ps. BR means books read and MD means money donated)

B: Write an equation showing the pattern from the table. Identify the variables.

C: Graph the equation.

Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0
The equation is y=5x
9 books =45
21 books =105

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The sum of two numbers is 49 and the difference between these two numbers is 9. What are these two numbers?​Shown working out pl
8_murik_8 [283]

Let numbers be x and y

ATQ

  • x+y=49---(1)

  • x-y=9---(2)

Adding both

\\ \sf\longmapsto 2x=58

\\ \sf\longmapsto x=\dfrac{58}{2}

\\ \sf\longmapsto x=29

Now putting value in eq(2)

\\ \sf\longmapsto x-y=9

\\ \sf\longmapsto 29-9=y

\\ \sf\longmapsto y=20

7 0
3 years ago
A recipe requires 4 cups of flour to make 3 dozen cookies. How many cups of flour are needed to make 10 dozen cookies?
VikaD [51]

9514 1404 393

Answer:

  13 1/3 cups

Step-by-step explanation:

We assume flour is proportional to cookies, so we have ...

  cups/dozens = x/10 = 4/3

Multiplying by 10 gives ...

  x = 40/3 = 13 1/3

13 1/3 cups of flour are needed for 10 dozen cookies.

6 0
3 years ago
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kramer
Value of y= 18 and value of x= 9 root3
therefore answer is D
7 0
2 years ago
A=pt+q<br> p= -1, t=4 and q=6<br> work out the value of a
77julia77 [94]

Answer:

a = 2

Step-by-step explanation:

a = pt + q

p = -1

t = 4

q = 6

a = -1(4)+6

a = -4+6

a = 2

8 0
3 years ago
Solve This Using The Quadratic Formula: 3x^2+9x-6=0
aivan3 [116]
<h3>Therefore either  x = \frac{-3+\sqrt{17}}{2}    or,  x = \frac{-3-\sqrt{17}}{2}</h3>

Step-by-step explanation:

3x^2 +9x -6=0                                x = \frac{-b\pm\sqrt{b^2- 4ac} }{2a}

\Leftrightarrow x = \frac{-9\pm\sqrt{9^2- 4.3(-6)} }{2.3}                     here a = 3 ,b = 9 and c= -6

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\Leftrightarrow x = \frac{3(-3\pm\sqrt{17}) }{6}

\Leftrightarrow x = \frac{-3\pm\sqrt{17}}{2}

Therefore either  x = \frac{-3+\sqrt{17}}{2}    or,  x = \frac{-3-\sqrt{17}}{2}

4 0
3 years ago
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