The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
Read more about Algebra Word Problems at; brainly.com/question/21405634
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Answer: e= 10
Step-by-step explanation:
To reduce the radical, you have to factorize 108.
108 is a multiple of 3, so to factorize it, you can divide it by 3
You can rewrite the square root as:
![\sqrt[]{3\cdot36}=\sqrt[]{3}\cdot\sqrt[]{36}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%5Ccdot36%7D%3D%5Csqrt%5B%5D%7B3%7D%5Ccdot%5Csqrt%5B%5D%7B36%7D)
The square root of 36 is equal to 6 so you can write the expression as:
![\sqrt[]{3}\cdot\sqrt[]{36}=6\sqrt[]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%7D%5Ccdot%5Csqrt%5B%5D%7B36%7D%3D6%5Csqrt%5B%5D%7B3%7D)
Answer and Step-by-step explanation:
Since we have given that
1. m∠1 + m∠5 = 180° and m∠1 + m∠4=180° - Given
2. m∠1 + m∠5 = m∠1 + m∠4 - Substitution
3. m∠5 = m∠4 -
Subtraction property of equality
4. Ray YZ is parallel to Ray UV - If alternate interior angles equal, then line are ||
