Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
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I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
Answer:
Step-by-step explanation:
5x+20 = 0
5X= -20
X= -20/5 = -4
8(4n+3) = 32n+24 =0
32n = -24
n = -24/32 = -3/4
12n-6=0
12n =6
n = 6/12 = 1/2
9(2x+9)
18x+81 =0
18x= -81
x= -81/18 = -9/2= -4.5
36+9y=0
36=-9y
36/-9 = y = -4
7(n-3) = 0
7n-21=0
7n = 21
n = 21/7
n=3
21+15a = 0
21= -15a
a= 21/-15 = 7/-5 = -1.4
32x-12x=0
20x=0
x=0/20 = 0
n-4-9=0
n-13=0
n=13
-3x-9+15x=0
-3x+15x-9 =0
12x-9=0
12x=9
x=9/12 = 3/4 = 0.75
-16N-14N=0
-30n=0
n=0/-30 =0
-10-90x-6x-10x²-2
-10-2-96x-10x²
-12-96x-10x²
10x²+96x+12
x= -b±√b²-4(a)(c)/2a
{-96±√96²-4(10)(12)}/2(10)
{-96±√(9216-480)}/20
-96±√8736/20
-96±(93.4665715644)/20
-96+93.4665715644/20 -96-93.4665715644/20
-2.5334284356/20 -189.466571564/20
-0.12667142178≅ -0.13 -9.4733285782≅ -9.47
-0.13 -9.47
-5(9n+9) =0
-45n-45 =0
-45n = 45
n = 45/-45 =-1
-5n+3(6+7n)
-5n+18+21n=0
-5n+21n+18 =0
16n+18 =0
16n = -18
n = -18/16 = -9/8 = -1.125
-4+7(1-3n)=0
-4+7-21n=0
3-21n=0
3=21n
3/21=n = 1/7
3n-(2n-8)
3n-2n+8=0
n+8=0
n=-8
Answer:
4x degrees= 52 degrees
(2x+12) degrees= 38 degrees
Step-by-step explanation:
4(13)=52
(2(13)+12)=38
<h3>Given :- </h3>
<h3>To Find :- </h3>
<h3>Solution :- </h3>
Let's Start :-
Putting the respective value of x we have ;
