AB and CD are common external tangents of R and S AB =15 SD=12 and SX=20 what is the measure of CX?

Mathematics

1 answer:

larisa [96]2 years ago

7 0

Answer:

Step-by-step explanation:

In circle S: XB and XD are tangents at B and D

then SB perpendicular to AX and SD perpendicular to XC

In triangle SDX: SD = 12 and SX =20 by using Pythagoras Theorem

$XD=\sqrt{20^{2} -12^{2} }=16$

XD = XB tangents to circle S from point X

XA = XC tangents to circle R from point X

then BA = DC = 15

then XC = XD + DC = 16 + 15 = 31

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simplifying further;