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olga_2 [115]
3 years ago
9

AB and CD are common external tangents of R and S AB =15 SD=12 and SX=20 what is the measure of CX?​

Mathematics
1 answer:
larisa [96]3 years ago
7 0

Answer:

31

Step-by-step explanation:

In circle S: XB and XD are tangents at B and D

then SB perpendicular to AX and SD perpendicular to XC

In triangle SDX:  SD = 12 and SX =20 by using Pythagoras Theorem

XD=\sqrt{20^{2} -12^{2} }=16

XD = XB  tangents to circle S from point X

XA = XC tangents to circle R from point X

then BA = DC = 15

then XC = XD + DC = 16 + 15 = 31

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\large\boxed{V=2304\pi}

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