I’m not sure that question.... sorry
Answer: Angle OZP= 62 Angle PZQ=63
(4r+2)+(5r-12)=125
9r-10=125
9r=135
r=15
Angle OZP Angle PZQ
4(15)+2 5(15)-12
62 63
Answer:
(x+3)(x-3)
Step-by-step explanation:
rewrite "9" as 3^2
so it is x^2-3^2
You use the difference of squares: a^2-b^2=(a+b)(a-b)
apply it: (x+3)(x-3)
Answer:
subtract 3 from both sides of the equation
Step-by-step explanation:
5x -3>2
+3. +3
5x>5
